Answer:
True
Step-by-step explanation:
The least total cost method is the method in which the total cost of the ordering cost and the total carrying cost is equal among various lot size available.
The order quantity should be choose when the total ordering cost and the total carrying cost equal to each other
The formula to compute the economic order quantity is shown below:
a. The computation of the economic order quantity is shown below:
![= \sqrt{\frac{2\times \text{Annual demand}\times \text{Ordering cost}}{\text{Carrying cost}}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%5Cfrac%7B2%5Ctimes%20%5Ctext%7BAnnual%20demand%7D%5Ctimes%20%5Ctext%7BOrdering%20cost%7D%7D%7B%5Ctext%7BCarrying%20cost%7D%7D%7D)
It is always be expressed in units
The formula to compute the ordering cost is
![= \frac{Annual\ demand}{Economic\ order\ quantity}\times ordering\ cost\ per\ order](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7BAnnual%5C%20demand%7D%7BEconomic%5C%20order%5C%20quantity%7D%5Ctimes%20ordering%5C%20cost%5C%20per%5C%20order)
And, the formula to compute the carrying cost is
![= \frac{Economic\ order\ quanity}{2}\times carrying\ cost\ per\ unit](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7BEconomic%5C%20order%5C%20quanity%7D%7B2%7D%5Ctimes%20carrying%5C%20cost%5C%20per%5C%20unit)
Hence, the given statement is true
Answer:
(3,-2)
Step-by-step explanation:
Given equations of line
3x-2y=13
2y+x+1=0
=> x = -1 -2y
Point of intersection will coordinates where both equation have same value of (x,y)
top get that we have to solve the both equations by using method of substitution of simultaneous equation.
using this value of x in 3x-2y=13, we have
3(-1-2y) -2y = 13
=> -3 -6y-2y = 13
=> -8y = 13+3 = 16
=> y = 16/-8 = -2
x = -1 - 2y = -1 -2(-2) = -1+4= 3
Thus, point of intersection of line is (3,-2)
10/22 in simplest form is 5/11
An ellipse (oval shape) is expressed by the following equation:
![\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2}=1](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28x-h%29%5E2%7D%7Ba%5E2%7D%20%2B%20%5Cfrac%7B%28y-k%29%5E2%7D%7Bb%5E2%7D%3D1%20)
where h is the x coordinate of the center and k is the y coordinate of the center. Furthermore, a is the horizontal distance from the center, and b is the vertical distance from the center. Lastly, c is the distance from the center to one of the foci (they are spaced apart equally).
We can find the foci by using
![a^2 - b^2 = c^2](https://tex.z-dn.net/?f=a%5E2%20-%20b%5E2%20%3D%20c%5E2)
36 - 11 =
![c^2](https://tex.z-dn.net/?f=c%5E2)
![c = \sqrt{25} = 5](https://tex.z-dn.net/?f=c%20%3D%20%20%5Csqrt%7B25%7D%20%20%3D%205)
Since the k value in this case is 0, the y value of both foci are 0. Also, since h and k are both 0, we know the center of the ellipse is at the origin.
So the foci are (-5, 0) and (5, 0)
Hope this helps :)