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olchik [2.2K]
3 years ago
15

Valeries employer covers 80% of the cost of a $4700 per year health insurance

Mathematics
1 answer:
kumpel [21]3 years ago
7 0
So, what exactly do you need help with..?
You might be interested in
3w + 7=8 need help with this
LiRa [457]
Hope this helps you out 3w+7=8

The answer is w= 1/3

Step by step:

3w+7=8
Step 1: is subtract is 7 from both sides.
3w+7-7=8-7
3w=1

Step 2: Divide both sides by 3.
3w/3 = 1/3

Your solution is:

w=1/3
6 0
3 years ago
Find the total area of the entire figure. *
bonufazy [111]

Answer:

392.5 in²

Step-by-step explanation:

This figure is consists of a trapezium and a rectangle.

So, to find the total area of the figure you have to find the area of the trapezium and the rectangle separately  and add them together.

Let us find now.

<u>Area of the Trapezium</u>

Area = \frac{1}{2} × ( sum of the parallel sides ) × height

Area = \frac{1}{2} × (  9 + 20 ) × 5

Area = \frac{1}{2} × 29 × 5

Area = \frac{1}{2} × 145

Area = 72.5 in²

<u>Area of the rectangle</u>

Area = Length × Width

Area = 20 × 16

Area = 320 in²

<u>Total area of the figure</u>

Total area = Area of the trapezium + Area of the rectangle

Total area = 72.5 in² + 320 in²

Total area = 392.5 in²

Hope this helps you :-)

Let me know if you have any other questions :-)

6 0
2 years ago
(t9)-8 what is the simplify expression
musickatia [10]
The answer would be -72t because all you would have to do is multiply the expression
7 0
3 years ago
Read 2 more answers
Solve for both systems: y+7z=22 and 8y + 7z = 127
7nadin3 [17]
Manipulate the first equation to
y = 22-7z

Then substitute in the second to find z
8(22-7z) + 7z = 127
176-56z+7z = 127
-49z = -49
z = 1

So y = 22-7(1) = 22-7 = 15

y = 15; z = 1
5 0
3 years ago
Read 2 more answers
The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
Anettt [7]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. Favorable cases for Both the laptops to be selected = _2C_2 = 1

Total number of cases = 15

Required probability is \frac{1}{15}.

b. Favorable cases for both the desktop machines selected = _4C_2=6

Total number of cases = 15

Required probability is \frac{6}{15} = \frac{2}{5}.

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

2. Both desktop:

Favorable cases = _4C_2=6

Total number of favorable cases = 8 + 6 = 14

Required probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

Total number of cases = 15

Required probability is \frac{8}{15}.

8 0
3 years ago
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