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Anna [14]
3 years ago
12

Evaluate the following. 106 A. 60 B. 100,000 C. 10,000 D. 1,000,000

Mathematics
2 answers:
Ivan3 years ago
7 0

Answer: the answer would be c

Step-by-step explanation:

Rufina [12.5K]3 years ago
7 0

Answer:  C) 1,000,000

Step-by-step explanation: usatestprep approved

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Jason spent $20.00 on Takis. If each bag of Takis cost
ddd [48]

Answer:

8

Step-by-step explanation:

20.00 divided 2.50 = 8.

7 0
3 years ago
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Please find the result !​
Sliva [168]

Answer:

\displaystyle - \frac{1}{2}

Step-by-step explanation:

we would like to compute the following limit:

\displaystyle  \lim _{x \to 0} \left( \frac{1}{  \ln(x +  \sqrt{  {x}^{2}  + 1} ) } -  \frac{1}{  \ln(x + 1) }  \right)

if we substitute 0 directly we would end up with:

\displaystyle\frac{1}{0}  -  \frac{1}{0}

which is an indeterminate form! therefore we need an alternate way to compute the limit to do so simplify the expression and that yields:

\displaystyle  \lim _{x \to 0} \left( \frac{ \ln(x + 1) -  \ln(x +  \sqrt{ {x}^{2} + 1 } }{  \ln(x +  \sqrt{  {x}^{2}  + 1} )  \ln(x + 1)  }  \right)

now notice that after simplifying we ended up with a<em> </em><em>rational</em><em> </em>expression in that case to compute the limit we can consider using L'hopital rule which states that

\rm \displaystyle  \lim _{x \to c} \left( \frac{f(x)}{g(x)}  \right)  = \lim _{x \to c} \left( \frac{f'(x)}{g'(x)}  \right)

thus apply L'hopital rule which yields:

\displaystyle  \lim _{x \to 0} \left( \frac{  \dfrac{d}{dx}  \ln(x + 1) -  \ln(x +  \sqrt{ {x}^{2} + 1 }  }{   \dfrac{d}{dx} \ln(x +  \sqrt{  {x}^{2}  + 1} )  \ln(x + 1)  }  \right)

use difference and Product derivation rule to differentiate the numerator and the denominator respectively which yields:

\displaystyle  \lim _{x \to 0} \left( \frac{ \frac{1}{x + 1}  -  \frac{1}{ \sqrt{x + 1} }  }{ \frac{ \ln(x + 1)}{ \sqrt{ {x}^{2}  + 1 }     }    +  \frac{  \ln(x +  \sqrt{x ^{2} + 1 }  }{x + 1} }  \right)

simplify which yields:

\displaystyle  \lim _{x \to 0} \left( \frac{ \sqrt{ {x}^{2} + 1  } - x - 1 }{  (x + 1)\ln(x  + 1 )  +  \sqrt{ {x}^{2}  + 1} \ln( x + \sqrt{ {x }^{2}  + 1} )   }  \right)

unfortunately! it's still an indeterminate form if we substitute 0 for x therefore apply L'hopital rule once again which yields:

\displaystyle  \lim _{x \to 0} \left( \frac{  \dfrac{d}{dx} \sqrt{ {x}^{2} + 1  } - x - 1 }{  \dfrac{d}{dx}  (x + 1)\ln(x  + 1 )  +  \sqrt{ {x}^{2}  + 1} \ln( x + \sqrt{ {x }^{2}  + 1}  )  }  \right)

use difference and sum derivation rule to differentiate the numerator and the denominator respectively and that is yields:

\displaystyle  \lim _{x \to 0} \left( \frac{  \frac{x}{ \sqrt{ {x}^{2} + 1 }  }  - 1}{      \ln(x + 1)   + 2 +  \frac{x \ln(x +  \sqrt{ {x}^{2} + 1 } ) }{ \sqrt{ {x}^{2} + 1 } } }  \right)

thank god! now it's not an indeterminate form if we substitute 0 for x thus do so which yields:

\displaystyle   \frac{  \frac{0}{ \sqrt{ {0}^{2} + 1 }  }  - 1}{      \ln(0 + 1)   + 2 +  \frac{0 \ln(0 +  \sqrt{ {0}^{2} + 1 } ) }{ \sqrt{ {0}^{2} + 1 } } }

simplify which yields:

\displaystyle - \frac{1}{2}

finally, we are done!

6 0
3 years ago
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Boxes that are 12 inches tall are being stacked next to boxes that are 18 inches tall. What is the shortest height qt which the
motikmotik

Answer:

The shortest height is 36 inches

Step-by-step explanation:

Here in this question, we want to know the shortest height with which boxes of 12 inches tall staked will be the same height with which boxes of 18 inches staked beside it

This is a question that has to do with multiples; In other words, we are simply looking for the lowest common multiple of 12 and 18;

The multiples of both are as follows;

12 - 12, 24,36,48,60•••••

18-18,36,54,72••••••

We can see that at the point 36, both have their first multiple match

So we can say that the lowest common multiple of 18 and 12 is 36

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3 years ago
The product of thirteen and a number
HACTEHA [7]
13x because you are saying the product of 13 that means 13x
6 0
3 years ago
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18 is what__ % of 30.
Nostrana [21]
18/30=?/100

18 times 100 = 1800

1800 divided by 30

60%
3 0
2 years ago
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