All categories

2 years ago

Jonathan fills 2/5 of a toffe box in 15 seconds. How many boxes can he fill in 10 minutes?

Mathematics

1 answer:

Zina [86]2 years ago

8 0

Answer:

16 boxes in 10 minutes

Step-by-step explanation:

2/5 = 15 sec

15 ÷ 2=7.5 1/5 = 7.5 seconds

7.5 × 5 = 37.5 37.5 = 1 box

60 × 10 = 600 secs

600 ÷ 37.5 = 16

16 boxes of toffee were made in 10 minutes

You might be interested in

Simplify 8x^4/x^3+7x^4 and Find the excluded values

Maksim231197 [3]

So first what we do is we need to get the excluded values. So to get them we have: 8x^4/x^3+7x^4.

Lets factor out the second part. x^3+7x^4 = (x^(3/4)+7x))^4

So then we get 8x^4/(x^(3/4)+7x)^4

8x^4/(x^(3/4)+7x)^4

8 0

2 years ago

Order these three values from least, middle, and greatest.

padilas [110]

Answer:

answer correct order 1,3,2

Step-by-step explanation:

65% of 80 is 52

82% of 50 is 41

and 170% of 30 is 51

7 0

2 years ago

3. Tickets to a show cost $5.50 for adults and 54.25 for students. A family is purchasing2

bulgar [2K]

Step-by-step explanation:The cost of an adult ticket to the show is $5.5

The cost of a student ticket to the show is $4.25

A family is purchasing 2 adult tickets and 3 student tickets. This means that the total cost of 2 adult tickets would be

2 × 5.5 = $11

It also means that the total cost of 3 student tickets would be

3 × 4.25 = $12.75

The total cost of 2 adult tickets and 3 student tickets would be

11 + 12.75 = $23.75

If the family pays $25, the exact amount of change they should receive is

25 - 23.75 = $1.25

7 0

2 years ago

What is the equation 12= x+ 3

IgorC [24]

X=12 because you would sub the 3 on both sides

3 0

2 years ago

The nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium. To determine if the

lora16 [44]

Answer:

We conclude that the sodium content is same as what the nutrition label states.

Step-by-step explanation:

We are given that the nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium.

The FDA randomly selects 40 packages of Oriental Spice Sauce and determines the sodium content. The sample has an average of 1088.64 milligrams of sodium per package with a sample standard deviation of 234.12 milligrams.

Let $\mu$ = average sodium content.

So, Null Hypothesis, $H_0$ : $\mu$ = 1100 milligrams {means that the sodium content is same as what the nutrition label states}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 1100 milligrams {means that the sodium content is different from what the nutrition label states}

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample average sodium content = 1088.64 milligrams

s = sample standard deviation = 234.12 milligrams

n = sample of packages of Oriental Spice Sauce = 40

So, test statistics = $\frac{1088.64-1100}{\frac{234.12}{\sqrt{40}}}$ ~ $t_3_9$

= -0.307

The value of z test statistics is -0.307.

Since, in the question we are not given the level of significance so we assume it to be 5%. Now, at 0.05 significance level the t table gives critical values of -2.0225 and 2.0225 at 39 degree of freedom for two-tailed test.

Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the sodium content is same as what the nutrition label states.

3 0

3 years ago