Acid rain, if I understand the question correctly.
Answer:
Frequency of B allele is 0.6681
Explanation:
If p represents the frequency of dominant allele and q represents the frequency of recessive allele, according to Hardy-Weinberg equilibrium:
p + q = 1
p² + 2pq + q² = 1
where p² = frequency of homozygous dominant genotype
q² = frequency of homozygous recessive genotype
2pq = frequency of heterozygous genotype
Given that number of recessive chestnut horse = 28
Total horses = 226 + 28 = 254
frequency of b² genotype = 28/254 = 0.1102
frequency of recessive b allele = √0.1102 = 0.3319
So, frequency of B allele =
1 - 0.3319 = 0.6681
Hence frequency of B allele is 0.6681
Answer:
r u on edg
Explanation: if its edg i know it
Answer:
by phenotypically identifying plants unable (or with an altered ability) to synthesize auxins. This approach is called reverse genetics
Explanation:
Reverse genetics is a strategy widely used in molecular genetics aimed at analyzing the function of target genes by identifying defective phenotypes of one or more organisms following the disruption of the gene. In this case, a mutagenesis approach (i.e., irradiation with X-rays) was used to induce mutations in the gene/s involved in auxin production. Subsequently, the resulting mutant phenotypes, i.e., plants with an altered ability to synthesize auxin, can be used to reveal the biological function of individual (mutated) gene sequences.
