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Mariana [72]
3 years ago
10

Which of the following is a/are question(s) that you should ask before you create an Access report?

Computers and Technology
1 answer:
never [62]3 years ago
5 0

Answer: All the above questions should be asked

Explanation:  Access report are the reports in access which provides the summarized and formatted information display in database. The information in the database is extracted from tables.The access report requires purpose of the report before preparation and the accessing users information to be known .

It is asked to make sure about that no unauthorized access of the report can take place. Distribution of the report among the other user or client is also a major question to be asked as to keep the record of the accessing of access report..Thus, all the question mentioned in the options are correct.

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Give 3 reasons why it is believed that smart phones precent us from communicating face to face.give three reasons why it is beli
gregori [183]

Answer:

yes

Explanation:

because the people will be lazy to go and talk to that person instead They will call each other and discuss

7 0
2 years ago
10. Question<br> What are the drawbacks of purchasing something online? Check all that apply.
max2010maxim [7]

Explanation:

1) the quality of purchased good may be low

2) there might me fraud and cheaters

3) it might be risky

4) we may not get our orders on time

7 0
2 years ago
How fast will a viral meme spread if it is not contained within 24 hours?
sveta [45]
Well a viral meme would spread very fast, it's a VIRAL meme which means it would spread faster than a normal meme. Even if it is contained in the 24 hour time period it would still become rather popular.
6 0
3 years ago
Read 2 more answers
Write a program that fills a list with 100 random numbers between 0 and 200, inclusive. Traverse through the list and only print
svet-max [94.6K]

Answer:

Follows are the code to this question:

import random as ra#import package  

r=[ra.randint(0, 200) for x in range(100)]#defining a variable r that use rand method to add value in list  

j= [i for i in r if i < 99]#defining j variable that checks list value is less than 99

print (j)#print list value

Output:

[20, 23, 66, 47, 89, 7, 18, 13, 92, 31, 23, 60, 3, 52, 18, 20, 85, 64, 55, 98, 14, 80, 80, 14, 57, 92, 76, 14, 91, 83, 87, 80, 16, 50, 7, 88, 19, 4, 72, 23, 27, 79, 23]

Explanation:

In this code, package random is imported, in the next step, the r variable is declared, that uses the randit method, and use for loop that adds value in the list. In the next step, the j variable is declared, which uses a for loop and a conditional statement to check its value is less than 99, add print its value.

7 0
2 years ago
Recall that within the ArrayBoundedQueue the front variable and the rear variable hold the indices of the elements array where t
Citrus2011 [14]

Answer:

int n = elements.length;

if(rear < n) {

rear = (rear + 1) % n;

elements[rear] = element;

rear = rear + 1;

}

Explanation:

Options are not made available; However, I'll answer the question base on the following assumptions.

Assumptions

Array name = elements

The front and the rear variable hold the current indices elements

Element to enqueue is "element" without the quotes

To enqueue means to add an element to an already existing queue or to a new queue.

But first, the queue needs to be checked if it can accept a new element or not; in other words, if it's full or not

To do this, we check: if rear < the length of the queue

If this statement is true then it means the array can accept a new element; the new element will be stored at elements[rear] and the rear will be icremented by 1 rear by 1

Else if the statement is false, then an overflow is said to have occurred and the element will not be added.

Going by the above explanation, we have

int n = elements.length;

if(rear < n) {

rear = (rear + 1) % n;

elements[rear] = element;

rear = rear + 1;

}

Additional explanation:

The first line calculates the length of the queue

The if condition on line 2 tests if the array can still accept an element or not

Let's assume this statement is true, then we move to liine 3

Line 3 determines the new position of rear.

Let's assume that n = 6 and current rear is 4.

Line 3 will produce the following result;

rear = (rear + 1) % n;

rear = (4 + 1)% 6

rear = 5%6

rear = 5.

So, the new element will be added at the 5th index

Then line 4 will be equivalent to:

elements[rear] = element;

elements[5] = element;

Meaning that the new element will be enqueued at the 5th index.

Lastly, rear is incremented by 1 to denote the new position where new element can be added.

6 0
3 years ago
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