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Vanyuwa [196]
3 years ago
11

A non-profit organization decides to use an accounting software solution designed for non-profits. The solution is hosted on a c

ommercial provider's site but the accounting information suchas the general ledger is stored at the non-profit organization's network. Access to the software application is done through an interface that uses a coneventional web browser. The solution is being used by many other non-profit. Which security structure is likely to be in place:
Computers and Technology
1 answer:
Mariana [72]3 years ago
8 0

Answer:

<em>A firewall protecting the  software at the provider</em>

Explanation:

The security structure that is likely to be in place is :<em>A firewall protecting the  software at the provider</em>

Since the access to the software application is via a conventional web browser, firewalls will be used in order to protect against unauthorized Internet users gaining access into the private networks connected to the Internet,

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1 - b - Excel is a computer program, so it'd be Software
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4 - c - A monitor will display (or output) an image based on what is received from the computer.
4 0
3 years ago
In this lab, you complete a C++ program that swaps values stored in three int variables and determines maximum and minimum value
Sergio039 [100]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

int first = 0,second = 0,third = 0;//defining integer variable  

int temp; //defining integer variable

const string SENTINEL = "done"; // defining a string variable as constant  

string repeat;// defining a string variable  

bool notDone = true; //defining bool variable

cout << "Enter first number: ";//print message

cin >> first;//input value

cout << "Enter second number: ";//print message

cin >> second;//input value

cout << "Enter third number: ";//print message

cin >> third;//input value

while(notDone == true)//defining a loop to check the value  

{

if(first > second)//use if to compare first and second value

{

int temp = first;//defining temp to hold first value

first = second;//holding second value in first variable

second = temp;//holding temp value in second variable

}

if(second > third)//use if to compare second and third value

{

int temp = second;//defining temp to hold second value

second = third;//holding second value in third variable

third = temp;//holding temp value in third variable

}

cout << "Smallest: " << first << endl;//print smallest value

cout << "Next smallest: " << second << endl;//print Next smallest value

cout << "Largest: " << third << endl;////print Largest value

cout << "Enter any letter to continue or done to quit: ";//print message

cin >> repeat;//holding string value

if (repeat == SENTINEL)

{

notDone = false;//holding bool value

}  

else //else block

{

cout << "Enter first number: ";//print message

cin >> first;//input value

cout << "Enter second number: ";//print message

cin >> second;//input value

cout << "Enter third number: ";//print message

cin >> third;//input value

}

return 0;

}

}

Output:

Please find the attached file.

Explanation:

  • Inside the main method Four integer variable "first, second, third, and temp" is declared in which first three variable is used for input value and temp is used to compare value.
  • In thew next step, two string variable "SENTINEL and repeat" is declared in which "SENTINEL" is constant and a bool variable "notDone" is declared.
  • After input the value from the user-end a loop is declared that compare and swap value and print its value.

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3 years ago
A company has a popular gaming platform running on AWS. The application is sensitive to latency because latency can impact the u
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3 years ago
Consider the partially-filled array named a. What does the following loop do? (cin is a Scanner object)int[] a = {1, 3, 7, 0, 0,
boyakko [2]

Answer:

Option 1: May crash at runtime because it can input more elements than the array can hold

Explanation:

Given the code as follows:

  1.        int[] a = {1, 3, 7, 0, 0, 0};
  2.        int size = 3, capacity = 6;
  3.        int value = cin.nextInt();
  4.        while (value > 0)
  5.        {
  6.            a[size] = value;
  7.            size++;
  8.            value = cin.nextInt();
  9.        }

From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.

However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist.  This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.  

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3 years ago
What is the output of this program?
Wewaii [24]

Answer:

6 +4 + 6 +4

Explanation:

It will start from index 0 and wherever you find the character inside the indexOf methods then you will note it down.

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4 years ago
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