Rate = 2 seats/11 minutes = 2/11 seats/min
Therefore the time required for s seats is
![(m \, min) = \frac{s \, seats}{ \frac{2}{11} \, \frac{seats}{min} } = \frac{11s}{2} \, min](https://tex.z-dn.net/?f=%28m%20%5C%2C%20min%29%20%3D%20%20%5Cfrac%7Bs%20%5C%2C%20seats%7D%7B%20%5Cfrac%7B2%7D%7B11%7D%20%5C%2C%20%20%5Cfrac%7Bseats%7D%7Bmin%7D%20%7D%20%3D%20%20%5Cfrac%7B11s%7D%7B2%7D%20%5C%2C%20min)
That is,
m = (11s)/2 min
When s = 16, obtain
![m = \frac{11(16)}{2} = 88 \, min](https://tex.z-dn.net/?f=m%20%3D%20%20%5Cfrac%7B11%2816%29%7D%7B2%7D%20%3D%2088%20%5C%2C%20min)
When s = 19, obtain
![m = \frac{11(19)}{2} = 104.5 \, min](https://tex.z-dn.net/?f=m%20%3D%20%20%5Cfrac%7B11%2819%29%7D%7B2%7D%20%3D%20104.5%20%5C%2C%20min)
Answers:
![m = \frac{11s}{2}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B11s%7D%7B2%7D%20)
When s = 16, m = 88 min
When s = 19, m = 104.5 min
Yes I just know I am in highshool
I took a look but could figure it out sorry
-0.8x-8.3=12.6
+8.3 +8.3
-0.8x=21
Divide by -0.8x on both sides
X=-26.25