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Advocard [28]
2 years ago
11

On Saturday, Alan traveled North along minor roads averaging 36 mph to visit a friend. On Sunday, he traveled East along main ro

ads averaging 60 mph to visit his mother. The trip to visit his mother was 24 miles longer and took 18 minutes less. How many miles was the trip (one-way) that Alan made on Saturday?
Mathematics
1 answer:
Dvinal [7]2 years ago
4 0

Answer: the trip (one-way) that Alan made on Saturday was 63 miles.

Step-by-step explanation:

Let x represent the distance of the trip that Alan made on Saturday.

Let t represent the time that it took Alan to make the trip on Saturday.

On Saturday, Alan traveled North along minor roads averaging 36 mph to visit a friend.

Distance = speed × time.

Therefore, distance travelled on Saturday would be

x = 36 × t = 36t

On Sunday, he traveled East along main roads averaging 60 mph to visit his mother. The trip to visit his mother was 24 miles longer and took 18 minutes(18/60 = 0.3 hours) less. This means that the distance travelled would be

x + 24 and the time spent would be t - 0.3 hours.

Distance travelled on Sunday would be

x + 24 = 60(t - 0.3)

x + 24 = 60t - 18 - - - - - - -- - - 1

Substituting x = 36t into equation 1, it becomes

36t + 24 = 60t - 18

60t - 36t = 24 + 18

24t = 42

t = 42/24 = 1.75

x = 36t = 36 × 1.75

x = 63 miles

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0.16

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Percent means 'per 100'. So, 16% means 16 per 100 or simply 16/100.

The answer is 0.16

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AT&T would like to test the hypothesis that the proportion of 18- to 34-year-old Americans that own a cell phone is less tha
Vera_Pavlovna [14]

Answer:

The null and alternative hypothesis can be written as:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.

This claim will be reflected in the alternnative hypothesis, that will state that the population proportion 1 (18 to 34) is significantly smaller than the population proportion 2 (35 to 49).

On the contrary, the null hypothesis will state that the population proportion 1 is ot significantly smaller than the population proportion 2.

Then, the null and alternative hypothesis can be written as:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0

The significance level is assumed to be 0.05.

The sample 1, of size n1=200 has a proportion of p1=0.63.

p_1=X_1/n_1=126/200=0.63

The sample 2, of size n2=175 has a proportion of p2=0.68.

p_2=X_2/n_2=119/175=0.68

The difference between proportions is (p1-p2)=-0.05.

p_d=p_1-p_2=0.63-0.68=-0.05

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{126+119}{200+175}=\dfrac{245}{375}=0.653

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.653*0.347}{200}+\dfrac{0.653*0.347}{175}}\\\\\\s_{p1-p2}=\sqrt{0.001132+0.001294}=\sqrt{0.002427}=0.049

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.05-0}{0.049}=\dfrac{-0.05}{0.049}=-1.01

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

\text{P-value}=P(z

As the P-value (0.1554) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.

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Step-by-step explanation:

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