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4 years ago

14

State the formula used for finding the area of a rectangle. Then apply the formula to find the area of the rectangle in the imag

e:

1 answer:

Anit [1.1K]4 years ago

8 0

The formula is L*H (LENGTH * HEIGHT) 9*4=36 THE AREA IS 36CM^2

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Jonas has 16 carnations and 12 roses. He wants to make identical bouquets for a party. How many bouquets can he make?

TiliK225 [7]

Answer:

Jonas can make 4 bouquets, each containing 4 carnations and 3 roses.

Step-by-step explanation:

Given that Jonas has 16 carnations and 12 roses, and he wants to make identical bouquets for a party, to determine how many bouquets can he make the following calculation must be performed, obtaining the largest common divisor between both numbers:

12 = Divisible by 2, 3, 4, 6 and 12

16 = Divisible by 2, 4, 8 and 16

Thus, the common greatest divisor between the two numbers is 4.

12/4 = 3

16/4 = 4

So, Jonas can make 4 bouquets, each containing 4 carnations and 3 roses.

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3 years ago

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4 years ago

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3 years ago

Solve this equation.<br> Y/4-4=5 y=

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Step-by-step explanation:

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3 years ago

In the xy coordinate plane the slope of line p is 1 2 and its x-intercept is -3. Find the equation of a line that is perpendicul

Novosadov [1.4K]

Answer:

Option C) y = -2x - 6

Step-by-step explanation:

<u><em>The correct question is</em></u>

In the xy coordinate plane the slope of line p is 1/2 and its x-intercept is -3. Find the equation of a line that is perpendicular to p and intersects p at is x-intercept.

step 1

Find the slope of a line that is perpendicular to p

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of the slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=\frac{1}{2}$ ----> slope of line p

substitute

$(\frac{1}{2})*m_2=-1$

$m_2=-2$ ----> slope of the line perpendicular to p

step 2

Find the equation of the line that is perpendicular to p and intersects p at is x-intercept

we have

$m=-2$

$point\ (-3,0)$

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

substitute

$y-0=-2(x+3)$

$y=-2x-6$

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4 years ago