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3 years ago

Find the x-intercept of the graph of the equation 2x - 5y = 10.

1 answer:

8 0

In order to find the x-intercept, you must plug in 0 for y.
2x - 5(0) = 10
2x = 10
Divide by 2 on both sides.
x = 5
Thus, the x-intercept is (5,0)

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alekssr [168]

Answer:

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Step-by-step explanation:

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Kayleigh babysat for 11 hours this week that was 5 fewer than 2/3 as manyas she baby sat last week, h write an equation to repre

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10.5 hours

Step-by-step explanation:

To find the number of hours she babysat last week subtract 5 from 11 which is 7 hours. 7 hours is equal to 2/3 of the many hours. If she babysat h hours last week then solve for h using 2/3 h = 7.

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Step-by-step explanation:

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3 years ago

To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and find

loris [4]

Answer:

Option D - $[0.12$

Step-by-step explanation:

Given : The manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s=0.16.

To find : The 95% confidence interval for the population standard deviation sigma?

Solution :

Number of sample n=19

The degree of freedom is Df=n-1=19-1=18

The standard deviation of the sample is s=0.16

Applying chi-square table to find critical value,

Upper critical value of $\chi^2$ is $UC=\chi(\frac{0.05}{2},18) = 31.5264$

Lower critical value of $\chi^2$ is

$LC=\chi(1-\frac{0.05}{2},18) = 8.2307$

Lower limit of the 95% confidence interval for the population variance

$L=\frac{(df)\times (s^2)}{UC}$

$L=\frac{18\times (0.16^2)}{31.5264}$

$L=\frac{18\times0.0256}{31.5264}$

$L=\frac{0.4608}{31.5264}$

$L=0.0146$

Upper limit of the 95% confidence interval for the population variance

$U=\frac{(df)\times(s^2)}{LC}$

$U=\frac{18\times (0.16^2)}{8.2307}$

$U=\frac{18\times0.0256}{8.2307}$

$U=\frac{0.4608}{8.2307}$

$U=0.0559$

So, The 95% confidence interval for the population variance is [0.0146, 0.0560]

Now, The 95% confidence interval for the population standard deviation is

$[\sqrt{0.0146}$

$[0.1208$

or $[0.12$

Therefore, Option D is correct.

The 95% confidence interval for the population standard deviation is $[0.12$

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3 years ago