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satela [25.4K]
3 years ago
13

A can of drink costs 32p. The cost of the drink has increased to 38p.

Mathematics
2 answers:
kkurt [141]3 years ago
3 0

Answer:

Jenny's percentage isn't correct

Step-by-step explanation:

You'd have to divide first:

38 / 32 = 1.1875 = (rounded) 1.19%

The percentage increase is 1.19%

Naya [18.7K]3 years ago
3 0

Answer:

the percentage is 100 because you add 32 and 38 and equals 100 if you were to subtract you would have got 6%

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

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This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

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(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

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Answer:

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Step-by-step explanation:

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7-3=4

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3 years ago
What a impor fraction
MrMuchimi
Im guessing you meant improper. This means that the numerator is greater than the denominator. An example is 11/4  
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shusha [124]

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She read 277 pages during the second week.

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