It would be 19/6 as an improper fraction and 3 & 1/6 as a mixed number fraction.
Answer:
X=5, Y=0
Step-by-step explanation:
-9Y +4X -20=0
-7Y+16X-80=0
1. We can multiply the first equation by 4. This will equal to -36Y +16X-80=0.
-36Y +16X -80 =0
-7Y+16X-80=0
2. We can subtract these two equations.
-36Y +16X -80 =0
-7Y+16X-80=0
We will get -29Y =0. Y=0.
3. Then we can substitute y into the first equation. -9(0) +4x-20 =0. 4x=20. x=5
X=5, Y=0
First of all, we need to know what a function is.
A function is a binary relation between two sets that
Answer: 60480
Step-by-step explanation:
Given : The number of empty seats in a theater = 9
The number of customers need to find places to sit =6
Since order matters here, so we use permutations
The permutations of n things taking r at a time is given by :-
![^nP_r=\dfrac{n!}{(n-r)!}](https://tex.z-dn.net/?f=%5EnP_r%3D%5Cdfrac%7Bn%21%7D%7B%28n-r%29%21%7D)
Then, the number of ways to arrange 6 seat in 9 seats :-
![^9P_6=\dfrac{9!}{(9-6)!}=\dfrac{9\times8\times7\times6\times5\times4\times3!}{3!}\\\\=60480](https://tex.z-dn.net/?f=%5E9P_6%3D%5Cdfrac%7B9%21%7D%7B%289-6%29%21%7D%3D%5Cdfrac%7B9%5Ctimes8%5Ctimes7%5Ctimes6%5Ctimes5%5Ctimes4%5Ctimes3%21%7D%7B3%21%7D%5C%5C%5C%5C%3D60480)
Hence, the number of ways to arrange 6 seat in 9 seats = 60480
If line segment EF is 28 and F is halfway through the line, then segment EF will be half of 28. So segment EF=14