Answer:
fx-6x+15
Step-by-step explanation:
fx-(6x-6)+9
fx-6x+6+9
fx-6x+(6+9)
fx-6x+15
Answer:
12. The second one
13. The first one
14. The last one
15. The first one
16. 30 degrees
Step-by-step explanation:
Answer:
Step-by-step explanation:
x
2
+
x
−
6
=
(
x
+
3
)
(
x
−
2
)
x
2
−
3
x
−
4
=
(
x
−
4
)
(
x
+
1
)
Each of the linear factors occurs precisely once, so the sign of the given rational expression will change at each of the points where one of the linear factors is zero. That is at:
x
=
−
3
,
−
1
,
2
,
4
Note that when
x
is large, the
x
2
terms will dominate the values of the numerator and denominator, making both positive.
Hence the sign of the value of the rational expression in each of the intervals
(
−
∞
,
−
3
)
,
(
−
3
,
−
1
)
,
(
−
1
,
2
)
,
(
2
,
4
)
and
(
4
,
∞
)
follows the pattern
+
−
+
−
+
. Hence the intervals
(
−
3
,
−
1
)
and
(
2
,
4
)
are both part of the solution set.
When
x
=
−
1
or
x
=
4
, the denominator is zero so the rational expression is undefined. Since the numerator is non-zero at those values, the function will have vertical asymptotes at those points (and not satisfy the inequality).
When
x
=
−
3
or
x
=
2
, the numerator is zero and the denominator is non-zero. So the function will be zero and satisfy the inequality at those points.
Hence the solution is:
x
∈
[
−
3
,
−
1
)
∪
[
2
,
4
)
graph{(x^2+x-6)/(x^2-3x-4) [-10, 10, -5, 5]}
Answer:
17.6%
Step-by-step explanation:
50×8%=4
75×24%=18
4+18=22
50+75=125
22÷125=17.6%
Answer:
The steps to finding the upper and lower quartiles are given in the first choice.
1. Order the data from least to greatest. If you don't do this, the data is random.
2. Find the median - you will do this so that you can find the midpoint of the data set (half of of the data is smaller and half of the data is larger).
3. Find the lower quartile - this is the half of the lower half of numbers; think of it as breaking the lower half of the data into 2 sections.
4. Find the upper quartile - this is the half of the greater half of numbers; this will break the upper half of the data into 2 sections.