Those are all lines...
So the x interval is from -2 to 3, because of x=-2 and x=3
The upper line is y(u)=4x and the lower line is y(l)=x-5
So the area between the two lines is:
A=⌠y(u)-y(l) dx
A=⌠4x-x+5 dx
A=⌠3x+5 dx
A=[3x^2/2+5x]
A=[(3x^2+10x)/2], x=[-2,3]
A=(1/2)(27+30-(12-20))
A=(1/2)(57+8)
A=(1/2)(65)
A=32.5 u^2
As it is, in accordance with the priorities of the operators (or the PEMDAS rule) the equation without parentheses mean
<span>(2/3)x+1=(1/6)x-7
I do not suppose you mean the above, since the solution is relatively trivial.
I suppose you actually mean
</span><span>2/(3x+1)=1/(6x-7)
in which case you would cross-multiply:
2(6x-7)=(3x-1)
and expand/distribute
12x-14=3x-1
isolate x and solve
12x-3x=-1+14
9x=13
x=13/9
If you mean the first form of equation without parentheses, my apologies.</span>
11.
(87+91+86+x)/4=90.
x=96.
13.
50×y > 130.
the lowest number could be 3, because 50×2=120, which is less than 130.
False. The postulate states: If two <span>
parallel</span> lines
are cut by a transversal, the interior angles on
the same side of the transversal are
supplementary.
Answer:
the answer is cubes curve
