120. (5 letters so 5*4*3*2*1)
1 . 5/6 + 2/3 = 5/6 + 4/6 = 9/6
2. D is correct
Hope it helps .....
A. answer question to problem
Answer:
No
Step-by-step explanation:
If A were reversible, then such y coudnt not exist, because A⁻¹y would be a solution of the equation Ax=y. This means that A in not reversible, thus, there exist a non zero vector w in R³ such that A*w = 0. If x' were a solution of Ax =z, then x'' = x'+w is a different solution of the equation: Ax'' = A(x'+w) = Ax'+Aw = z+0 = z. This means that a vector z such that there exist a unique solution for the equation Ax=z cant exist.
F(x)=(x-10)(x+6) and set it equal to 0 you will get x-10=0 and x+6=0 so x=10 and x=-6