Answer:
1. 3/25
2. 22/25
3. 2/25
4. 7/50
5. 1 6/25
Step-by-step explanation:
It's true
collinear means they are on the same line so ST=SU
so if ST= 50 then SU=50 making T the midpoint of line that is 100
s----------------t-----------------u
50 50
a - length of side of a square
t - length of side of a triangle
The perimeter of a square: ![P_S=4a](https://tex.z-dn.net/?f=P_S%3D4a)
The perimeter of a triangle: ![P_T=3t](https://tex.z-dn.net/?f=P_T%3D3t)
We have the area of a triangle: ![A_T=16\sqrt3\ cm^2](https://tex.z-dn.net/?f=A_T%3D16%5Csqrt3%5C%20cm%5E2)
The formula of an area of an equilateral trinagle: ![A_T=\dfrac{t^2\sqrt3}{4}](https://tex.z-dn.net/?f=A_T%3D%5Cdfrac%7Bt%5E2%5Csqrt3%7D%7B4%7D)
Substitute:
<em>multiply both sides by 4</em>
<em>divide both sides by
</em>
![t^2=64\to t=\sqrt{64}\to t=8\ cm](https://tex.z-dn.net/?f=t%5E2%3D64%5Cto%20t%3D%5Csqrt%7B64%7D%5Cto%20t%3D8%5C%20cm)
The perimeter of a triangle: ![P_T=3(8)=24\ cm](https://tex.z-dn.net/?f=P_T%3D3%288%29%3D24%5C%20cm)
Substitute to the formula of a perimeter of a square:
<em>divide both sides by 4</em>
![a=6\ cm](https://tex.z-dn.net/?f=a%3D6%5C%20cm)
The formula of a diagonal of a square: ![d=a\sqrt2](https://tex.z-dn.net/?f=d%3Da%5Csqrt2)
Substitute:
![d=6\sqrt2\ cm](https://tex.z-dn.net/?f=d%3D6%5Csqrt2%5C%20cm)
Answer:
area = 8x^2 - 2x - 15
Step-by-step explanation:
area = length x width
area = (2x-3) x (4x+5)
area = 8x^2 + 10x - 12x - 15
reduce:
area = 8x^2 - 2x - 15