Please show how to compute these values. Thank you.

Brian bought a tablet that was discountedby 15%. the tablet normally sells for y dollars. eith tax, Brian paid $309. if the tax

sertanlavr [38]

309-20 x .15
but yeah

3 0

3 years ago

PLSSSS HELP Which statement is true about the ratios shown?

Fiesta28 [93]

despacito

3 0

2 years ago

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What is the area of the figure shown?

Anni [7]

The triangle is 3x10/2 = 15 ft.

The rectangle is 5x10 = 50 ft.

Total = 65 ft.

7 0

3 years ago

BRAINLIEST for the correct answer!

Vladimir [108]

Answer:

answer is A

Step-by-step explanation:

(3 $x^{2}$ +5x+1) ( $x^{2}$ −2x+4)

=(3 $x^{2}$ +5x+1)( $x^{2}$ +−2x+4)

=(3 $x^{2}$ )( $x^{2}$ )+(3 $x^{2}$ )(−2x)+(3 $x^{2}$ )(4)+(5x)( $x^{2}$ )+(5x)(−2x)+(5x)(4)+(1)( $x^{2}$ )+(1)(−2x)+(1)(4)

=3 $x^{4}$ −6 $x^{3}$ +12 $x^{2}$ +5 $x^{3}$ −10 $x^{2}$ +20x+ $x^{2}$ −2x+4

=3 $x^{4}$ − $x^{3}$ + 3 $x^{2}$ + 18x +4

4 0

3 years ago

In the figure, PQ is parallel to RS. The length of RP is 2 cm; the length of PT is 18 cm; the length of QT is 27 cm. What is the

Sidana [21]

Step 1

Find the value of TS

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

so

$\frac{TR}{TP} =\frac{TS}{QT}$

solve for TS

$TS =\frac{TR*QT}{TP}$

we have

$RP=2\ cm\\TP=18\ cm\\QT=27\ cm$

$TR=TP+RP\\TR=18+2=20\ cm$

substitute

$TS =\frac{20*27}{18}$

$TS =30\ cm$

Step 2

Find the value of SQ

we know that

$SQ=TS-QT$

we have

$TS =30\ cm$

$QT=27\ cm$

substitute

$SQ=30\ cm-27\ cm=3\ cm$

therefore

the answer is

the value of SQ is $3\ cm$

6 0

3 years ago

Read 2 more answers