Answer:

Step-by-step explanation:
Assuming that the metal frame is a square metal frame because the length of the side of the metal frame is given.
Given:
Radius of the mirror = 2x unit
Side length of the square metal frame = 12x unit
We need to find the area of the metal frame.
Solution:
First we find the area of the circular mirror, using area formula of the circle.

Where, r = Radius of the object.
Substitute r = 2x in above equation.



Now, we find the area the square, using area formula of the square.



So, the area of the square metal frame is given as






Therefore, the area of the metal frame is
.