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Sphinxa [80]
3 years ago
8

The picture explains it

Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

60

Step-by-step explanation:

you know that if one line is perpendicular to another line, and another line is perpendicular to that line, they are all perpendicular (90). so, all corners are right angles. that means that angle AGD is 90. so, if you know 30, then subtract 30 from 90 and you get that angle AGF is 60. then, because angle AGF and angle EGB are vertical angles, they are congruent, so x is 60.

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What is the slope of the line passing through the points (−3, 4) and (4, −1)?
Igoryamba
Note:
The slope of a straight line passing through the points (x₁, y₁) and (x₂, y₂) is 
m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

The two given points are (-3,4) and (4,-1). Therefore the slope is
m= \frac{-1-4}{4-(-3)} = \frac{-5}{7}

Answer: - \frac{5}{7}

3 0
3 years ago
Can someone help me with my homework please?
grigory [225]
Multiplying x^2 by 5 stretches the graph vertically by a factor of 5.  Try graphing both x^2 and 5x^2 and see for yourself that this is correct.
3 0
3 years ago
Y is equal to the additive inverse of 4x. Use this information to find the value of the expression 17x + 3y in terms of x.
nevsk [136]

Answer:

<h3>5x</h3>

Step-by-step explanation:

The additive inverse of a function is that value added that will sum it up to zero

If y is the  additive inverse of 4x, then y = -4x

Given the expression 17x+3y

Substitute y = -4x into the expression to have;

17x + 3(-4x)

17x -12x

5x

Hence the value of the expression in terms of x is 5x

5 0
2 years ago
Can someone help I will give the brainliest Plz help u will get 50 points
lara [203]

Answer:

B.) 6

2.) 70

3.) 56

Step-by-step explanation:

B.) 2(6) - 6

= 12 - 6

=6

2.) 7(2(3)+4)

=7(6+4)

=42+28

=70

3.) 10(3) + 4(3) + 14

= 30 + 12 + 14

= 42+14

=56

Have a wonderful day

:)

7 0
3 years ago
A) Divide 20 in the ratio 2:3
Keith_Richards [23]

Answer:

a=8:12      c=£1.05:0.70  d=30:50:60:40

b=9:15

Step-by-step explanation:

8 0
3 years ago
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