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trasher [3.6K]
3 years ago
5

What is the slope of the line passing through the points (−3, 4) and (4, −1)?

Mathematics
1 answer:
Igoryamba3 years ago
3 0
Note:
The slope of a straight line passing through the points (x₁, y₁) and (x₂, y₂) is 
m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

The two given points are (-3,4) and (4,-1). Therefore the slope is
m= \frac{-1-4}{4-(-3)} = \frac{-5}{7}

Answer: - \frac{5}{7}

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Find the equation of the line that passes through the point (-2,7) and is perpendicular to the line y= 2/5x-1/5
-BARSIC- [3]

Step-by-step explanation:

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3 0
3 years ago
Can someone answer this please
ollegr [7]
The answer is symmetric because it’s equal
7 0
3 years ago
Suppose KLMN ~ PQRS. Find the value of x.
arlik [135]

Complete question is attached.

Answer:

B) 8

Step-by-step explanation:

In this question, KLMN ~ PQRS. This means they are similar shapes.

From the image, we could denote that:

KL ~ PQ

LM ~ QR

Given that:

KL = 12

PQ = 30

QR = 20

LM = x

To find x, let's use tge expression:

\frac{KL}{PQ} = \frac{LM}{QR}

=  \frac{12}{30} = \frac{x}{20}

Cross multiplying, we have:

12 * 20 = 30x

240 = 30x

To find x, let's divide both sides by 30.

\frac{240}{30} = \frac{30x}{30}

8 = x

x = 8

The correct option is option B.

3 0
3 years ago
Factor completely: −3x2 + 6x − 9
denis23 [38]
Factor out the -3
(-3)(x^2-2x+3)

8 0
3 years ago
Read 2 more answers
Cho tam giác ABC vuông tại A đường giao AH biếtAH=12cm BH=9cm.<br><br>Tính diện tích tam giác ABC
Lostsunrise [7]

Answer:

Step-by-step explanation:

AB^2 = HB^2 + AH^2 => AB = 15cm

Ta co cong thuc: 1/AH^2 = 1/AB^2 + 1/AC^2 => AC=20cm

Vay SABC= 1/2 .AB.AC = 1/2 .15.20=150cm^2

6 0
2 years ago
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