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Marina86 [1]
3 years ago
13

Which of these number(s) below are potential roots of the function p(x)=x^4+22x^2-16x-12

Mathematics
2 answers:
S_A_V [24]3 years ago
7 0

Answer:

6, 1,3

Step-by-step explanation:

Alex Ar [27]3 years ago
3 0

There's no list so we'll generate our own. Technically we're after zeros of p(x), which are the roots of p(x)=0.


The rational zeros are always fractions with a factor of the constant in the numerator and of the leading term in the denominator. Here we have a monic polynomial, leading coefficient 1, so the rational roots are all integers, factors of -12.


The potential rational zeros are: -12, -6, -3, -2, -1, 1, 2, 3, 6, 12



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Step-by-step explanation:

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Find the value of 1×4+2×5+3×6......n×(n+3)​
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n(n+1)(n+5)/3

Step-by-step explanation:

there is no value, as we don't know n.

but we can create a summary formula/ function definition :

this is the sum for k = 1 to n of k×(k+3)

k×(k+3) = k² + 3k

so, the overall sum splits into the sum of k² for k=1 to n, and the sum of 3k for k=1 to n.

and the sum of 3k is 3 times the sum of k for k=1 to n.

Σk² for k=1 to n = [n(n+1)(2n+1)]/6

Σk for k=1 to n = n(n+1)/2

3×Σk for k=1 to n = 3×n(n+1)/2

so, we have a function formula

n(n+1)(2n+1)/6 + 3n(n+1)/2 = n(n+1)(2n+1)/6 + 9n(n+1)/6 =

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3 0
3 years ago
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Answer:

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Step-by-step explanation:

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where n = number of sides

Here you have :

(5 - 2)*180 = 540°

3 0
3 years ago
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