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KATRIN_1 [288]
3 years ago
10

162 ⋅ 90 238·56 238 ⋅ 34 =

Mathematics
2 answers:
ollegr [7]3 years ago
6 0

1572455566080 is your answer! Hope I helped! :D

nlexa [21]3 years ago
6 0

Answer:

2.7952024e+13

Step-by-step explanation:


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2 years ago
A hardware supplier manufacturers 3 kinds of clamps types AB &c production restrictions force it to make 10 more type C clam
hichkok12 [17]

Answer:

Hardware supplier will manufacture 60 Type A clamps, 180 Type B clamps and 150 Type C clamps.

Step-by-step explanation:

Given:

Company produces 3 types of clamp

Type A

Type B

Type C

production restrictions force it to make 10 more type C clamps in the total of the other types

Hence We can say that Clamp C is equal to sum of Clamp A and Clamp and 10

framing in equation form we get;

C=A+B+10 \ \ \ \ \ equation \ 1

Also Given:

3 times as many Type B clamps as type A clamps

Hence we can say that Clamp B is equal to thrice of Clamp A.

B=3A \ \ \ \ equation\ 2

Also Given

Total Number of Clamps  = 490

Hence Total  Number of Clamps  is equal to sum of number of Clamps of Type A, Type B and Type C.

Framing in equation form we get;

A+B+C =490 \ \ \ \ equation \ 3

Substituting the equation 1 and Equation 2 in equation 3 we get

A+B+C=490\\\\A+3A+A+B+10=490\\\\A+3A+A+3A+10=490\\\\8A = 490-10\\\\8A=480\\\\A=\frac{480}{8}=60

Now Substituting the Value of A in equation 2 we get;

B=3A = 3\times60 =180

Now Substituting the values of A and B in equation 1 we get:

C=A+B+10 = 60+180+10= 250

Now checking the same we get;

A+B+C=490\\60+180+250=490\\490=490

Hence the Hardware supplier will manufacture 60 Type A clamps, 180 Type B clamps and 150 Type C clamps.

5 0
3 years ago
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