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Strike441 [17]
3 years ago
12

The conversion of ammonium cyanide to urea is a second-order reaction. This means that the concentration C of ammonium cyanide a

t time t is given by 1/C = kt + 1/C0, where C0 is the initial concentration and k is the rate constant. Assume the initial concentration is known to be 0.1 mol/L exactly. Assume that time can be measured with negligible uncertainty.
a. After 45 minutes, the concentration of ammonium cyanide is measured to be 0.0811 ? 0.0005 mol/L. Estimate the rat? constant k, and find the uncertainty in the estimate.

b. Use the result in part (a) to estimate the time when the concentration of ammonium cyanide will be 0.0750 mol/L, and find the uncertainty in this estimate.
Mathematics
1 answer:
sergejj [24]3 years ago
6 0

Answer:

your answer could be A

Step-by-step explanation:

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Create an equation to solve for x using the trapezoid midsegment formula:
Serggg [28]

Answer:

Equation for x:    3x - 6 = \frac{2x - 1 + 25}{2}

x = 9

CD = 17

GH = 21

Step-by-step explanation:

The midsegment formula for a trapezoid is

GH = \frac{CD + FE}{2}

3x - 6 = \frac{2x - 1 + 25}{2}

6x - 12 = 2x + 24

4x = 36

x = 9

CD = 2x - 1 = 2(9) - 1 = 18 - 1 = 17

GH = 3x - 6 = 3(9) - 6 = 3 = 27 - 6 = 21

4 0
3 years ago
There is one fifth of a sandwich to share equally between 2 people. How much of the sandwich will each person get? Use the numbe
babunello [35]

Answer:

one tenth of a sandwich

Step-by-step explanation:

4 0
3 years ago
Solve for the smallest value of $x$ such that $24x^2 + 17x - 20 = 0.$ Express your answer as a simplified common fraction.
Gala2k [10]
X=5/8 or x=-4/3 
here is the work if needed...
24x^2+17x-20=0
Step one: Factor left side of equation.
(8x-5)(3x-4)=0
Step two: Set factor equal to 0.
8x-5=0 or 3x-4=0
x=5/8 or x=-4/3
4 0
3 years ago
The length of a photograph is 1 cm less than twice the width. The area is 91cm^2. Find the width and length.
Brums [2.3K]
Let the width = x
=>length = 2x-1

91= x(2x-1)=2x^2-x
2x^2-x-91=0
=(2x+13)(x-7)
=> x=-13/2=> no
=>x= 7 cm
7 0
3 years ago
Write the first five terms of the sequence defined by the explicit formula
denis-greek [22]

<u>Answer:</u>

The correct answer option is: 19, 13, 3, -11, -29.

<u>Step-by-step explanation:</u>

We are given the following explicit formula for an arithmetic sequence:

a_n=21-2n^2

So to find the first five terms of this sequence, we will substitute the values of n (num here in the given formula:

a_1=21-2(1)^2\\\\a_1=19


a_2=21-2(2)^2\\\\a_2=13


a_3=21-2(3)^2\\\\a_3=3


a_4=21-2(4)^2\\\\a_4=-11


a_5=21-2(5)^2\\\\a_5=-29

Therefore, the first five terms of the sequence defined by the explicit formula a_n=21-2n^2 are 19, 13, 3, -11, -29.


5 0
3 years ago
Read 2 more answers
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