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Strike441 [17]
3 years ago
12

The conversion of ammonium cyanide to urea is a second-order reaction. This means that the concentration C of ammonium cyanide a

t time t is given by 1/C = kt + 1/C0, where C0 is the initial concentration and k is the rate constant. Assume the initial concentration is known to be 0.1 mol/L exactly. Assume that time can be measured with negligible uncertainty.
a. After 45 minutes, the concentration of ammonium cyanide is measured to be 0.0811 ? 0.0005 mol/L. Estimate the rat? constant k, and find the uncertainty in the estimate.

b. Use the result in part (a) to estimate the time when the concentration of ammonium cyanide will be 0.0750 mol/L, and find the uncertainty in this estimate.
Mathematics
1 answer:
sergejj [24]3 years ago
6 0

Answer:

your answer could be A

Step-by-step explanation:

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The net of a pyramid is shown below:
Stells [14]

Answer:

245 square inches

Step-by-step explanation:

4(1/2×7×14)+(7×7)

4 0
3 years ago
Find the value of the constant m √150 - √12m + √54 = 0​
Tomtit [17]

Answer:

<u>m</u><u> </u><u>is</u><u> </u><u>√</u><u>2</u>

Step-by-step explanation:

{ \tt{ \sqrt{150}  -  \sqrt{12}m +  \sqrt{54}  = 0 }} \\ { \tt{ \sqrt{12}m } =  \sqrt{150}  -  \sqrt{54} } \\ { \tt{ (\sqrt{4 \times 3}) m = ( \sqrt{25 \times 6} ) - ( \sqrt{9 \times 6}) }} \\ { \tt{( \sqrt{4 \times 3} )m = 5 \sqrt{6}  - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3}m = 5 \sqrt{6}   - 3 \sqrt{6} }} \\ { \tt{2 \sqrt{3} m = 2 \sqrt{6} }} \\ { \tt{ \sqrt{3}  m =  \sqrt{6} }} \\ { \tt{ \sqrt{3} m = ( \sqrt{3} \times  \sqrt{2} ) }} \\ { \tt{m =  \sqrt{2} }}

7 0
3 years ago
Write an expression so that when you divide ¼ by a number the quotient will be greater than 1/4.
SVETLANKA909090 [29]
Hello There!

An example of this would be:
\frac{6}{1/4}
6 = \frac{6}{1}
\frac{6}{1} *  \frac{4}{1}
= \frac{24}{1}
= 24

Hope This Helps You!
Good Luck :) 

- Hannah ❤
8 0
3 years ago
Their can u please solve.
Bingel [31]

Answer:

\frac{45}{9} = 5

4 0
3 years ago
Read 2 more answers
Dario bakes a lasagna containing 2/3 pound of parmesan cheese, 5/4 pounds of ricotta cheese, and 4/3 pounds of mozzarella cheese
kap26 [50]
First, we have to figure out how much cheese we have total. Do this by adding up all of the various cheeses.

\frac{2}{3}  +  \frac{4}{3}  +  \frac{5}{4} \\  \frac{6}{3}  + 1 +  \frac{1}{4}  \\ 3 \frac{1}{4}
Now to split the cheeses into sections of 1/4 pound each, we have to divide by 1/4, which is the same as multipling by 4

3 \frac{1}{4}  \times 4 = 12 + 1 = 13

13 slices total
5 0
3 years ago
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