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2 years ago

15

Look at the shaded triangle. Describe two ways of drawing the square design below using any combination of translation , reflect

ion ,and rotations of figure I (the shaded triangle).

1 answer:

densk [106]2 years ago

7 0

The first way:
1. Reflect the figure I across the x-axis.
2. Translate the figure I and its reflection and rotate them 90 degrees.

The second way:
1. Reflect the figure I across the x-axis.
2. Rotate 90 degrees counterclockwise.
3. Rotate it across the y-axis.

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Can someone please help me.. very quickly .. thank you

Alisiya [41]

X/8 + 12 = 16
start by subtracting twelve from both sides
x/8 + 12 = 16
- 12 -12
You're left with x/8 = 4
Multiply both sides by 8
8× x/8 = 4 ×8
Your answer is x = 32
If you need to simplify, the answer is 2.

3 0

2 years ago

Read 2 more answers

Solve the inequality. Graph the solution. Describe the graph in the area provided. Be sure to indicate where there is an open or

natka813 [3]

Step-by-step explanation:

The given inequality is :

$-27\ge \dfrac{1}{2}(6x-12)$

Solving RHS of the inequality:

$-27\ge \dfrac{1}{2}\times 2(3x-6)\\\\-27\ge (3x-6)$

Adding 6 both sides of the inequality

$-27+6\ge (3x-6)+6\\\\-21\ge 3x\\\\x\le -7$

The attached figure shows the graph for the given inequality.

7 0

2 years ago

Please help<br> Find the value of X

const2013 [10]

Answer:

23

Step-by-step explanation:

7 0

2 years ago

Determine whether the given expressions are perfect square trinomials. Write "P" if it is a perfect square trinomial and "N" if

Sav [38]

1) P
2) P
3)N
4)N
5) P
Hope this helps

8 0

3 years ago

There are two vendors at the fair sleeping snow cones for the same price. If the containers are completely filled and then level

aliya0001 [1]

Answer:

$d = 787.81cm^3$

Step-by-step explanation:

Given

See attachment for the containers

Required

The difference in the amount of snow cone they hold

The amount they hold is determined by calculating the volume of the containers.

The traditional snow cone has the following dimension

Shape: Cone

$r=4cm$ --- radius

$h = 13cm$ --- height

The volume is calculated as:

$Volume = \frac{1}{3} \pi r^2h$

So, we have:

$V_1 = \frac{1}{3} \pi * 4^2 * 13$

$V_1 = \frac{208}{3} \pi$

The snow cone in a cup has the following dimension

Shape: Cylinder

$r=8cm$ --- radius

$h = 5cm$ --- height

The volume is calculated as:

$Volume = \pi r^2h$

So, we have:

$V_2 = \pi *8^2 * 5$

$V_2 = \pi *320$

$V_2 = 320\pi$

The difference (d) in the amount they hold is:

$d = V_2 - V_1$

$d = 320\pi - \frac{208\pi}{3}$

Take LCM

$d = \frac{3*320\pi -208\pi}{3}$

$d = \frac{960\pi -208\pi}{3}$

$d = \frac{752\pi}{3}$

Take $\pi = 22/7$

$d = \frac{752}{3} * \frac{22}{7}$

$d = \frac{752 * 22}{3*7}$

$d = \frac{16544}{21}$

$d = 787.81cm^3$

4 0

2 years ago