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Semenov [28]
2 years ago
5

Find the value of x. M1= 3x + 7 and m5 = 25

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
7 0

Answer:

x=9

Step-by-step explanation:

m5=m1 so

25=3x+7

18=3x

x=9

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Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants. 37 x2 − 6x
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Answer:

\dfrac{A}{x}+\dfrac{B}{x-6}

Step-by-step explanation:

Given the function \dfrac{37}{x(x-6)}, to write the form of its partial fraction on decomposition, we will separate the two functions separated by an addition sign. The numerator of each function will be constants A and b and the denominator will be the individual factors of each function at the denominator. The partial fraction of the rational function is as shown below.

= \dfrac{37}{x(x-6)}\\\\= \dfrac{A}{x}+\dfrac{B}{x-6}

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3 years ago
A seamstress has 1/4 of a foot of thread. Then she uses 1/5 of a foot of thread to sew a hole. How much of the thread is left?
Ilya [14]
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3 0
3 years ago
Use the diagram to answer the question
koban [17]

Answer:

m\angle EFG=52^{o}

Step-by-step explanation:

We have been given that line m is parallel to line p, m\angle HEF=39^{o} and m\angle IGF=13^{o}.

Since line m is parallel to line p and EJ is a transversal, so measure of angle EJG will be 39 degrees as angle EJG is alternate interior angle of angle HEF. Both angles are inside parallel lines m and p and on opposite side of transversal EJ.

We can see that angle EFG is exterior angle of triangle GFJ. Since the measure of an exterior angle of a triangle equals to the sum of the opposite interior angles.

We can see that angle IGF and angle EJG are opposite interior angles of angle EFG.

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Upon substituting our given values we will get,

m\angle EFG=13^{o}+39^{o}

m\angle EFG=52^{o}

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