3x - 4y = 8
y = mx + b ; m is the slope ; b is the y-intercept
-4y = -3x + 8
y = -3x/-4 + 8/-4
<span>y = 3/4 x - 2</span>
Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
The answer is <span>49x2 _ 84x + 36
</span>
(7x - 6)² is the square of the difference. The general formula would be:
(a - b)² = a² - 2ab + b²
In our expression (7x - 6)², a would be 7x and b would be 6:
(7x - 6)² = (7x)² - 2 · 7x · 6 + 6²
= 7² · x² - 84x + 36
= 49x² - 84x + 36
The correct answer is 10! Just asked Siri!
2 over 7 =0,28
9/0,28=32,14
Hope it helped
