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valentinak56 [21]
2 years ago
10

Solve this equation x/4-20=-12

Mathematics
2 answers:
Ad libitum [116K]2 years ago
7 0

Answer:

x = 32

Step-by-step explanation:

Find a common denominator

x/4 + 4 ( -20 )/4 = -12

Combine fractions with denominator

Multiply the numbers

Multiply all terms by the same value to eliminate fraction denominators

Cancel multiplied terms that are in the denominator

Multiply the numbers

Add 80 to both sides of the equation

Then simplify!

Naddika [18.5K]2 years ago
6 0

Answer:

X=32

Step-by-step explanation:

First Find common denominator

Combine fractions with common denominator

Multiply the numbers

Multiply all terms by the same value to eliminate

And I think you got it from there :))))))))))))))

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A woman bought some large frames for $10 each and some small frames for $5 each add a closeout sale if she bought 20 frames for
vampirchik [111]

Answer:

The quantity of large frames is 7

The quantity of small frames is 13

Step-by-step explanation:

Given as :

The price of each large frames = $ 10

The price of each small frames = $ 5

The total number of both frames bought = 20

The price for both the frames = $ 135

Now,

Let the quantity of large frames = L

And The quantity of small frames = S

So , According to question

The total number of both frames bought = 20

Or, The quantity of large frames + the quantity of small frame = 135

Or, L + S = 20         ......A

And $ 10 L + $ 5 S = $ 135                         ................B

Or, $ 10× ( L + S ) = $ 10× 20

Or, $ 10 L + $ 10 S = $ 200

(  $ 10 L + $ 10 S ) - ( $ 10 L + $ 5 S ) = $ 200 - $ 135

Or , ( $ 10 L - $ 10 L ) + ( $ 10 S - $ 5 S ) = $ 65

Or, 0 + 5 S = 65

∴  S = \frac{65}{5}

I.e S = 13

So, The quantity of small frames = S = 13

Put the Value of S in eq A

So , L + S = 20

Or, L = 20 - S

Or, L = 20 - 13

∴   L = 7

So, The quantity of large frames = L = 7

Hence The quantity of large frames is 7

And   The quantity of small frames is 13   Answer

7 0
3 years ago
Jodie read 42 randomly chosen books from each library in her city. Each library is the same size.
ahrayia [7]

Answer:

Yes!

Step-by-step explanation:

The definition of Representative is

A representative sample is a group or set chosen from a larger statistical population or group of factors or instances that adequately replicates the larger group according to whatever characteristic or quality is under study

so your book is whats understudy and with that you'll know that yes, yes it is

3 0
3 years ago
Find the diameter of a circle with a circumference of 15.17 yards
Aleksandr-060686 [28]

Answer:

4.83

Step-by-step explanation:

To find the circumference of a circle you need to take the diameter times Pi. So if you need to find the diameter from the circumference, simply divide the circumference by 3.14 which is Pi

Hope this helps!

7 0
3 years ago
Which of the following must be true?
meriva

Answer:

BC < ED ⇒ answer A

Step-by-step explanation:

* Lets revise some facts in the triangle

- If one side of a triangle is longer than another side, then the angle

 opposite the longer side will be larger than the angle opposite the

 shorter side

- If one angle in a triangle is larger than another angle in a triangle,

 then the side opposite the larger angle will be longer than the side

 opposite the smaller angle

* Lets solve the problem

- In the two triangles BCD and DEB

∵ CD = 8 and BE = 8

∴ CD = BE

∵ Side BD is a common side in the two triangles

- The third side in Δ BCD is BC and the third side in DEB is DE

∵ BC is the opposite side to the angle of measure 24°

∵ ED is the opposite side to the angle of measure 30°

∵ The measure 24° < the measure 30°

∴ The side opposite to the angle of measure 24° < the side opposite

   to the angle of measure 30°

∵ The other two sides of the 2 triangles BCD and DEB are equal

∴ We can compare between the 3rd sides in the Δ BCD and Δ DEB

∴ BC < ED

7 0
2 years ago
Verify that the given value is the solustion of the equation x=6 for 2z-4=8​
klemol [59]

Answer:

8-4=2z.. 2z+4=6 so x=6

6 0
3 years ago
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