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Delvig [45]
3 years ago
12

What is the solution of sqrt (x-4)+5=2

Mathematics
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

x = 13

Step-by-step explanation:

<em>sqrt (x-4) + 5 = 2</em>

<em>The equation is √(x+4) + 5 = 2</em>

√(x-4) = 2 - 5

√(x-4) = -3

x-4 = (-3)²

x-4 = 9

x = 9 + 4

x = 13

Therefore, the second option x = 13 is correct.

!!

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How to use distributive property to remove the parentheses
GrogVix [38]

Answer: Multiply the number(s) outside the parenthesis by the numbers inside the parenthesis. The distributive property is expressed in math terms as the following equation: a(b + c) = ab + ac.

Step-by-step explanation:

2(3 + 4) - 12 Multiply 2 times 3 first.

2 x 3 = 6.

Then multiply 2 times 4.

2 x 4 = 8.

Remember our equation earlier? a(b + c) = ab + ac.

In this case, 2 is a, 3 is b, and 4 is c.

So 2[a](3[b]+4[c]) = 2[a](3)[b] + 2[a](4)[b].

Let's rewrite this in a way that can be read better.

2(3+4) - 12 = 2(3) + 2(4) - 12.

2(3+4) - 12 = 6 + 8 - 12.

2(3+4) - 12 = 14 - 12.

2(3+4) - 12 = 2.

Hope this helped! :)

4 0
3 years ago
The product of two numbers is 144, but their sum is -24. What are these two numbers?
stepladder [879]

Answer:

The two numbers are - 12 and - 12 .

Step-by-step explanation:

Let the two numbers be x and y then

By the question

x * y = 144

or x = 144 / y ....... I)

Again

x + y = - 24

Or 144/y + y = - 24

or, ( 144 + y²) / y = - 24

or, 144 + y² = - 24y

y² + 24y + 144 = 0

y² + ( 12 + 12 ) y + 144 =0

y² + 12y + 12y + 144 = 0

y(y + 12 ) + 12 ( y + 14) = 0

( y + 12 ) ( y + 12 ) = 0

Either

y + 12 =0

y = - 12

Now

x = 144 / - 12 = - 12

Therefore the two numbers are - 12 and - 12 .

Hope it will help :)❤

4 0
3 years ago
I WILL GIVE BRAINLEST AND POINTS 20??
earnstyle [38]

Answer:

The formula for the volume of a cube is-

side length^3.

For your problem side length=4, so the answer is 4^3=64

Answer: 64 cu. cm

Step-by-step explanation:

6 0
3 years ago
What is the equation of the line that passes through the point (-2,14) and is perpendicular to the line with the following equat
tino4ka555 [31]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{5}}x-1\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-2}{5}} ~\hfill \stackrel{reciprocal}{\cfrac{5}{-2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{5}{-2}\implies \cfrac{5}{2}}}

so we're really looking for the equation of a line whose slope is 5/2 and it passes through (-2 , 14)

(\stackrel{x_1}{-2}~,~\stackrel{y_1}{14})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{5}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{14}=\stackrel{m}{ \cfrac{5}{2}}(x-\stackrel{x_1}{(-2)}) \implies y -14= \cfrac{5}{2} (x +2) \\\\\\ y-14=\cfrac{5}{2}x+5\implies {\Large \begin{array}{llll} y=\cfrac{5}{2}x+19 \end{array}}

3 0
1 year ago
Mr. Fairfax ordered 3 large pizzas. group a ate 6/6 of the first pizza , group b ate 8/6 of the remaining pizza. how much pizza
Nezavi [6.7K]
They would would have eaten 4/6

3 0
3 years ago
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