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Veronika [31]
2 years ago
8

Find the value of this expression if x = -6. x^2-3/x+3 Enter the correct answer.

Mathematics
1 answer:
Amanda [17]2 years ago
6 0

Answer:

\frac{x^{2}-3}{x+3}=\frac{(-6)^{2}-3}{-6+3}\\\\=\frac{36-3}{-3}=\frac{33}{-3}=-11

Step-by-step explanation:

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Select all the statements that are true about standard deviation.
frozen [14]

Answer:

A,B, C

Step-by-step explanation:

hope it helps

7 0
2 years ago
(6 1/3-1/6x 36=?<br> 221/6<br> 216<br> 222<br> 242
scoundrel [369]

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8 0
2 years ago
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
2 years ago
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