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Nadya [2.5K]
3 years ago
12

Write an equation of a line that is perpendicular to the x-axis and passes through (-3, 1)

Mathematics
1 answer:
zavuch27 [327]3 years ago
4 0
For a line to be perpendicular to the x-axis in a 2 dimensional space, it must be composed of points with the same x coordinate and varying in the y coordinate.
X is, therefore, a constant and since the line goes through (-3,1), the equation we are looking for is:

X = -3
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dsp73

Answer:

t = 7

Step-by-step explanation:

5(2t - 3) – 7.5t = 0.5(12 – t)

5*2t - 3*5 - 7.5t = 12*0.5 - t *0.5

10t - 15 - 7.5t = 6 - 0.5t           {Now, combine like terms}

10t - 7.5t - 15 = 6 - 0.5t

         2.5t -15 = 6 - 0.5t      {Add 15 to both sides}    

         2.5t      = 6 - 0.5t + 15

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                 3t = 21     {Divide both sides by 3}

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6 0
3 years ago
The assumption that YZ is perpendicular bisector of AX is not enough to show hat YXZ equals YAZ
d1i1m1o1n [39]
<span>The assumption that YZ is perpendicular bisector of AX is not enough to show hat YXZ equals YAZ is false</span>
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3 years ago
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Answer:

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