okay well first you should put it in slope-intercept form aka y = mx + b
but you have simplify everything first
2(x + 3) + 2(y + 2) = 16
2x + 3 + 2y + 4 = 16
2x + 2y + 7 = 16
-7 -7
2x + 2y = 9
-2x -2x
2y = -2x + 9
/2 /2
y = -x + 4.5
so now in a graph it should look like this:
To solve this equation , we need to write it in quadratic form
To get the equation in quadratic form we replace x^2 with u
can be written as
, Replace u for x^2
So equation becomes
Now we factor the left hand side
-16 and -1 are the two factors whose product is +16 and sum is -17
(u-16) (u-1) = 0
u -16 = 0 so u=16
u-1 =0 so u=1
WE assume u = x^2, Now we replace u with x^2
Now take square root on both sides , x= +4 and x=-4
Now take square root on both sides , x= +1 and x=-1
So zeros of the function are -4, -1, 1, 4