Find the value of the expression below. log4 3 + log4 8 - log4 6

2 answers:

7 0

The question can be solved as:

log4^3 + log4^8 - log4^6
= 3log4 + 8log 4 - 6 log4
(Because log n ^ m = m log n)
= 5 log 4
= 5log (2^2)
(Because 4 can be written as 2^2)
= 5*2 log 2
= 10 log 2
= 10*0.3010
(Because log 2 = 0.3010)
= 3.010

julsineya [31]3 years ago

4 0

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expeople1 [14]

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at x = 3, the graph does cross the x-axis, meaning it has an odd multiplicity, could be 3 or 1, or 7 or 9, but let's use 1.

$\bf \begin{cases} x=-1\implies &x+1=0\\ x=3\implies &x-3=0 \end{cases}~\hspace{5em}\stackrel{\textit{even multiplicity}}{(x+1)^2}\qquad \stackrel{\textit{odd multiplicity}}{(x-3)^1}=\stackrel{y}{0} \\\\\\ (x^2+2x+1)(x-3)=y\implies x^3+2x^2+x-3x^2-6x-3=y \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x^3-x^2-5x-3=y~\hfill$