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tankabanditka [31]
3 years ago
13

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
Leona [35]3 years ago
6 0

Answer:

1 and 4 are correct. 2 and 3 are not.

Step-by-step explanation:

1.

When x = 0 where does the horse start?

y = 1.5*sin(0 + 0.5)*2*pi + 1.5

y = 1.5*sin(0.5*2pi) + 1.5

y = 1.5*sin(pi) + 1.5 But sin pi = 0

y = 0 + 1.5 So the horse is starting at the midpoint of it's travel.

2.

This one is a trick question. You can reason it without exact answers. At some point the sin(x + 0.5)*2pi will equal 1. When it does 1.5 * 1 + 1.5 = 3.0 At some other point sin(x + 0.5)*2pi = -1. When that happens the whole thing goes to 0. So the total of the distance traveled is 6 not three.

3.

You can figure this one out by letting x = 0.01 When it does then the value of the function is

y = 1.5*sin [(0.01 + 0.5)*2pi] + 1.5

y = 1.5*sin(0.51*2*pi) + 1.5

y = 1.5*sin(3.204424) + 1.5

y = 1.5*(- .0623) + 1.5

y = -0.9418 + 1.5

y = 1.4058 so it is going downward The value is getting smaller.

4.

The horse starts out in the middle of the pole. What  does x need to equal so that x + 0.5 = 1 ? And why 1. The answer to why 1 is that then the sine function will equal sin(2*pi)

That happens when x = 0.5 which is 1/2 a minute. If it takes 1/2 a minute to execute 1 complete cycle, then in 5 minutes the cycle will be executed 10 times. This one is correct.


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faust18 [17]

Given equation : n(17+x)=34x−r.

We need to solve it for x.

Distributing n over (17+x) on left side, we get

17n + nx  = 34x - r.

Adding r on both sides, we get

17n+r + nx  = 34x - r+r.

17n + r + nx = 34x.

Subtracting nx from both sides, we get

17n + r + nx-nx = 34x-nx

17n + r = 34x -nx.

Factoring out gcf x on right side, we get

17x + r = x(34-n).

Dividing both sides by (34-n), we get

\frac{(17x + r)}{(34-n)} = \frac{x(34-n)}{(34-n)}

\frac{(17x + r)}{(34-n)} = x

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7 0
3 years ago
Read 2 more answers
Which of the following represents the zeros of f(x) = x3 − 11x2 + 38x − 40?
Delvig [45]
The answer is <span>5, 4, 2
</span>
Among all choices we have 5, so
x = 5
x - 5 = 0
Let's divide the expression by (x - 5) using the long division:
                          x³ - 11x² + 38x - 40
(x - 5)  * x² =      x³ - 5x²                   Subtract
____________________________
                              -6x² + 38x - 40
   (x - 5) * (-6x) =    -6x² + 30x          Subtract
____________________________
                                           8x - 40
                    (x - 5) * 8 =     8x - 40   Sutract
____________________________
                                              0

Thus: x³ - 11x² + 38x - 40 = (x - 5)(x² - 6x + 8)

Now, let's simplify x² - 6x + 8.

x² - 6x + 8 = x² - 2x - 4x + 8 =
                  = x² - 2*x - (4*x - 4*2) = 
                  = x(x - 2) - 4(x - 2) =
                  = (x - 4)(x - 2)

Hence:
x³ - 11x² + 38x - 40 = (x - 5)(x - 4)(x - 2)
To calculate zero:
x³ - 11x² + 38x - 40 = 0
(x - 5)(x - 4)(x - 2) = 0
x - 5 = 0            or             x - 4 = 0              or      x - 2 = 0
x = 5                 or              x = 4                   or      x = 2
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Step-by-step explanation:

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