Answer:
The shortest walking route is through the diagonal AC: 102.89m
Step-by-step explanation:
One can go from A to C using 2 paths:
- ADC or ABC
- using diagonal AC and half of that inner circle.
We need to compute the length of each path.
1) ADC=AD+DC=80+50=130m
2) AC²=AD²+DC²=80²+50⁵=6400+2500= 8900m²
AC=sqrt(8900)=94.34m.
Note that the diagonal AC has a missing segment, whose length is the diameter of the inner circle. So the straight line has a length of: AC-d=94.34-15=79.34m.
Perimeter of half the circle=pi×r= 3.14×(15/2)= 3.14×7.5=23.55m
So, if one is using the diagonal to go from A to C, then he has to walk:
79.34+23.55=102.89m
Comparing the two routes: 130m vs 102.89m, we notice that the route using the diagonal AC is shorter.
Answer:
171.65
Step-by-step explanation:
A=2AB+(a+b+c)h
AB=s(s﹣a)(s﹣b)(s﹣c)
s=a+b+c
2
Solving forA
A=ah+bh+ch+1
2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=5·10+5·10+5·10+1
2·﹣54+2·(5·5)2+2·(5·5)2﹣54+2·(5·5)2﹣54≈171.65064
Answer:
4x(3a+2b)
Step-by-step explanation:
Answer:
he worked 4 hours each day
Step-by-step explanation:
