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Natali [406]
3 years ago
7

Answer fast please I want to be done with my hw

Mathematics
1 answer:
Ket [755]3 years ago
6 0

Answer:b

Step-by-step explanation: $0.50 a year

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The length of a rectangular garden is 33 m greater than the width. the area is 7070 msquared2. find the dimensions of the garden
11Alexandr11 [23.1K]
How can I help you today
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3 years ago
A right circular cylinder has a height of ​ 19 3/4 ​ ft and a diameter ​ 1 2\5 ​ times its height.
alexira [117]

Answer:

Volume of cylinder is  34833.21 ft³

Step-by-step explanation:

Given : A right circular cylinder having height 19\frac{3}{4} ft and diameter \frac{12}{5} ​times its height.

Given : diameter \frac{12}{5} ​times its height that is

diameter \frac{12}{5} ​times  19\frac{3}{4}  that is

Diameter = \frac{12}{5} \times \frac{79}{4} ​

Diameter = \frac{237}{5} ft

Radius is half of diameter,

Radius = \frac{1}{2} \times \frac{237}{5}=\frac{237}{10} ft

\text{Volume of Cylinder}=\pi r^2h

Substitute the values, we get,

\text{Volume of Cylinder}= \pi (\frac{237}{10})^2 \times \frac{79}{4}

\text{Volume of Cylinder}= \times 3.14 \times (23.7)^2 \times 19.75

\text{Volume of Cylinder}= \times 3.14 \times (23.7)^2 \times 19.75

\text{Volume of Cylinder}=34833.21

Thus, volume of cylinder is  34833.21 ft³


6 0
3 years ago
Use the set of clues in the equations below to find the value of each variable .
soldier1979 [14.2K]
There are many ways to solve this problem. All you have to do is simple algebraic manipulation. Solve for b and h with the two simpler equations:
2b = 12; divide 2 on both sides to get b = 6
h - x = 2; add x to both sides to get h = (2 + x)

Plug this stuff into the first equation to solve for x. Once we solve for x, we can plug that x value into the equation for h. Because you can see we didn’t get an actual numerical value for h. So:
x + (2+x) + 6 = 14
Subtract 6 from both sides and distribute that plus sign to get rid of the parenthesis. Then combine the like terms to get:
2x + 2 = 8
Subtract 2 from both sides and divide by 2 to get x = 3

Finally plug it into the equation for h:
h = 2+3 = 5
4 0
3 years ago
The variable $x$ varies directly as the square of $y$, and $y$ varies directly as the cube of $z$. If $x$ equals $-16$ when $z$
Kisachek [45]

If x varies directly as y^2, then there is some constant a for which

x=ay^2

Similarly, there is some constant b such that

y=bz^3

Given that x=-16 when z=2, we have

\begin{cases}-16=ay^2\\y=8b\end{cases}\implies-16=a(8b)^2\implies ab^2=-\dfrac14

Now when z=\frac12, we get

\begin{cases}x=ay^2\\y=\frac b8\end{cases}\implies x=a\left(\dfrac b8\right)^2=\dfrac{ab^2}{64}=\dfrac{-\frac14}{64}=\boxed{-\dfrac1{256}}

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3 years ago
Solve the triangle. Round decimal answers to the nearest tenth​
Lana71 [14]

Answer:

my answer is in this picture

6 0
3 years ago
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