Answer:
We have the system:
x ≤ 7
x ≥ a
Now we want to find the possible values of a such that the system has, at least, one solution.
First, we should look at the value of a where the system has only one solution:
We can write the 2 sets as:
a ≤ x
x ≥ 7
So, writing both together:
a ≤ x ≤ 7
if a is larger than 7, we do not have solutions.
then a = 7 gives:
7 ≤ x ≤ 7
Here the only solution is 7.
Now, if a is smaller than 7, for example 5, we have:
5 ≤ x ≤ 7
Now x can take different values, so we have a lot of solutions.
Then the restrictions for a, such that the system has at least one solution, is:
a ≤ 7.
Answer:
Step-by-step explanation:
1.
19² = 17² +x²
19² - 17² = x²
√361-289 =x
√72 = 8.5 ≈ x
Area = base*h/2 = 17*8.5/2 ≈ 72.3
Perimeter = 19+17+8.5= 44.5
and so on...
2.
x²= 5² +13²...
A= 5*13/2 =...
P= 5+13+x=...
3.
20² = 10² +x²...
A=10*x/2=...
P=20+10+x=...
4.
x² = 5² +14²...
A=5*14/2 =...
P= 5+14+x = ...
This was to raise revenue for the British Empire by taxing the North American colonies.
Answer:
4y(7y - 6)
Step-by-step explanation:
Answer:
3.07091228=x
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp/ adj
tan 21 = x/8
8 tan 21 =x
3.07091228=x
