A = k/R where A = acceleration and R = radius of the turn and k is a constant to be found.
Substituting the given values:-
10 = k / 70
k = 10*70 = 700
So the equation of the motion is A = 700 / R
When the radius is 140 the acceleration is 700 / 140 = 5 ft/sec/sec ( answer)
remember: a filled dot means it includes that point and an empty dot means it doesn't
A. has empty dot at 0 so x=0 is not incuded in the solution
B. has filled dot at x=0 so x=0 is a solution
C. has empty dot at 0 so x=0 is not incuded in the solution
D. the line doesn't even go over x=0 so not a solution
answer is B
Answer:
Step-by-step explanation:
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Answer:
thethe answer is the 3rd one
