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4 years ago

Please answer and work out for 45points

Mathematics

1 answer:

Katyanochek1 [597]4 years ago

4 0

43) is equal cause 3/4 is like quarters you have 3 and equals 75 cents and that's where that .75 comes from

44) they are not equal 7/20 is .35

45) they are not equal 11/21 is .52381

46) they are equal because 4/5 is .8

47) they are equal because 11/40 is .275

48) they are not equal because 21/25 is .84 and then add 1 and it would be 1.84

49) they are not equal because 16/25 is .64

50) they are equal because 7/20 is .35

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Round to the nearest tenth.

laila [671]

Answer:

8.2 units

Step-by-step explanation:

Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC

Recall the Law of Cosines

$a^2=b^2+c^2-2bc\cdot cos(A)$

Identify angles and sides

$m\angle A=23^\circ\\a=BC=?\\b=AC=14\\c=AB=6$

Solve for side "a"

$a^2=b^2+c^2-2bc\cdot cos(A)\\\\a^2=14^2+6^2-2(14)(6)\cdot cos(23^\circ)\\\\a^2=196+36-168cos(23^\circ)\\\\a^2=222-168cos(23^\circ)\\\\a=\sqrt{222-168cos(23^\circ)}\\ \\a\approx8.2$

Therefore, the length of line segment BC is about 8.2 units

8 0

2 years ago

PLEASE HELP

Pavel [41]

Answer:

15.06

Step-by-step explanation:

I don't have a step-by-step explanation, but i hope this helps!!!

7 0

3 years ago

Choose the model that shows 11/10-3/10

Bas_tet [7]

Answer:

The third model

Step-by-step explanation:

I'm pretty sure it is, I can't see all of them tho

6 0

3 years ago

Read 2 more answers

Which is the graph of f(x) = 5(2)x?

Yuliya22 [10]

Slope:-2
y-intercept:5

7 0

3 years ago

Use the Rational Zero Theorem to list all possible rational zeros for the given function. f(x) = 10x^5 + 8x^4 - 15x^3 +2x^2 - 2

vagabundo [1.1K]

Given:

The function is:

$f(x)=10x^5+8x^4-15x^3+2x^2-2$

To find:

All the possible rational zeros for the given function by using the Rational Zero Theorem.

Solution:

According to the rational root theorem, all the rational roots are of the form $\dfrac{p}{q},q\neq 0$ , where p is a factor of constant term and q is a factor of leading coefficient.

We have,

$f(x)=10x^5+8x^4-15x^3+2x^2-2$

Here,

Constant term = -2

Leading coefficient = 10

Factors of -2 are ±1, ±2.

Factors of 10 are ±1, ±2, ±5, ±10.

Using the rational root theorem, all the possible rational roots are:

$x=\pm 1,\pm 2,\pm \dfrac{1}{2}, \pm \dfrac{1}{5},\pm \dfrac{2}{5},\pm \dfrac{1}{10}$ .

Therefore, all the possible rational roots of the given function are $\pm 1,\pm 2,\pm \dfrac{1}{2}, \pm \dfrac{1}{5},\pm \dfrac{2}{5},\pm \dfrac{1}{10}$ .

5 0

3 years ago