Answer:
The Margin of Error in percentage is 5.88%
Step-by-step explanation:
The values of the factors in the question are;
The mean increase in price per share, = $1.95
The number of companies in the sample, n = 100
The mean increase in price per share,
= $1.82
The standard deviation of the population, σ = $0.30
The margin of error, MOE, is given by the following formula;
![Margin \ of \ Error= z \times \dfrac{\sigma}{\sqrt{n} }](https://tex.z-dn.net/?f=Margin%20%5C%20of%20%5C%20Error%3D%20z%20%5Ctimes%20%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%20%7D)
Where;
z = z-score, critical value = 1.96 at 95%
σ = The standard deviation of the population = $0.30
n = The sample size = 100
Therefore, we have;
![Margin \ of \ Error= 1.96 \times \dfrac{0.3}{\sqrt{100} } = 0.0588](https://tex.z-dn.net/?f=Margin%20%5C%20of%20%5C%20Error%3D%201.96%20%5Ctimes%20%5Cdfrac%7B0.3%7D%7B%5Csqrt%7B100%7D%20%7D%20%3D%200.0588)
The Margin of Error in percentage = 0.0588 × 100 = 58.8%
The Margin of Error in percentage = 5.88%