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Lerok [7]
3 years ago
8

Please help me please

Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0

we are given

sum of three consecutive numbers are 303

Let's assume

first term is a-d

second term is a

third term is a+d

now, we can add them

a-d+a+a+d=303

3a=303

a=101

so, middle term is 101

so, largest term will be greater than middle term

so, largest term must be greater than 101

so, option-A........Answer

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Read 2 more answers
URGENT WILL MARK BRAINLIEST <br>Show your work and solve for x and y.<br>3x + y = 8<br>2x + 4y = 12​
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2x+4y=12

  • x+2y=6--(2)

  • (1)×1 and (2)×3

\\ \rm\Rrightarrow 3x+y=8

\\ \rm\Rrightarrow 3x+6y=18

Subtract both

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\\ \rm\Rrightarrow y=\dfrac{-10}{-5}

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3 0
2 years ago
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