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astra-53 [7]
3 years ago
9

True or False: The endpoints of a polygon must conform to snap points, whereas the edges of an area are not confined by snap poi

nts.
Mathematics
2 answers:
netineya [11]3 years ago
8 0

Answer: It is false , trust  me

Step-by-step explanation:

fgiga [73]3 years ago
3 0

For this case, what we should know is that a polygon is a geometric figure with n sides that is closed. It is usually the union of straight lines.

On the other hand, in order to find the area of a figure, we need it to be closed.

Therefore, the edges of an area are confined by snap points.

Answer:

FALSE

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Ben walks 25 miles from home to work. If he walks the first 5 miles in 1 hour, the second 5 miles in 1.4 hours, the third 5 mile
natka813 [3]

<u>Answer:</u>

The total time taken to complete 25 miles is 7.6 hours.

Solution:

Ben walks 5 miles in 1 hour,

Second 5 miles in 1.4 hours,

Third 5 miles in 1.7 hours,

Last 5 miles in 1.8 hours

So he walked total 20 miles in (1+1.4+1.7+1.8) hours = 5.9 hours = 6 hours (approximately)

So his average speed is \left(\frac{20}{6}\right) miles/hours = 3.33 miles/hours.  

i.e. he travels 3.3 miles in 1 hour,

Then, he travels 1 miles in \left(\frac{1}{3.3}\right) hours

Hence the total time he will take to walk 25 miles is \left(25 \times\left(\frac{1}{3.3}\right)\right) \text { hours }\Rightarrow \left(\frac{25}{3.3}\right) \text { hours } = 7.5757 hours

That is approximately 7.57 or 7.6 hours.

8 0
3 years ago
Find two unit vectors orthogonal to both given vectors. i j k, 4i k
Maurinko [17]
The cross product of two vectors gives a third vector \mathbf v that is orthogonal to the first two.

\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k

Normalize this vector by dividing it by its norm:

\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)

To get another vector orthogonal to the first two, you can just change the sign and use -\mathbf v.
6 0
3 years ago
Is this answer correct?​
disa [49]

Answer: ya

Step-by-step explanation:

5 0
3 years ago
Help Pls! It's for my Math 4! Scalar Multiplication!
prohojiy [21]

Answer:

Concept: Physics Qualitative Analysis.

  • Scalar values are constant and compared to vector values they do not have a direction or magnitude or a gradient representation.
  1. Lets get started by setting up the equation
  2. They want us to find 3U-2V
  3. Given U= <6,6> V=<6,-6>
  4. Now we plug in and solve!
  5. 3<6,6>- 2<6,-6>
  6. <18,18>-<12,-12>
  7. Subtract
  8. <18-12,18-(-12)>
  9. Hence that gives us a result of <6,30>
  10. Now with the skills you gained solve the rest!!!
8 0
3 years ago
Read 2 more answers
Hese are the values in Paul’s data set.
andrew-mc [135]
Answer: See description below.

The residuals are the differences between the predicted values and the actual values. You will need to make a scatter plot of each difference.

Here are the five points that you will need to plot:
20 - 21 = -1  (1, -1)
17 - 16 = 1 (2, 1)
9 - 10 = -1 (4, -1)
6 - 5 = 1 (5, 1)
2 - 2 = 0 (6, 0)
8 0
3 years ago
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