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amid [387]
3 years ago
8

Two squares have perimeters of 25 yards and 100 yards respectively. How many times greater is the perimeter of the larger square

?
Mathematics
2 answers:
stepan [7]3 years ago
7 0
It would be 8 times greater
AlexFokin [52]3 years ago
6 0

Answer: the answer would be 8. if i helped, please give brainliest! x

Step-by-step explanation:

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-2018/2017 is irrational.
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It has 3 sides and the measure is 3

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A pack of 5 smiley stickers cost $6.50. What is the unit price?
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2 years ago
I need help............​
Alexxandr [17]

Problem 35

The bar graph is shown below

You simply draw various rectangles such that the heights represent the frequency of each animal type.

Eg: there are 20 elephants, so the "elephant" bar is 20 units tall.

You can make the bar graph by hand, or use spreadsheet software. I recommend going with software (if you can).

=======================================================

Problem 36

1 book = 20 mm thickness

5 books = 5*20 = 100 mm thickness

1 paper = 0.016 mm thickness

5 papers = 5*0.016 = 0.08 mm thickness

total thickness = 100+0.08 = 100.08 mm

<h3>Answer: 100.08 mm</h3>

=======================================================

Problem 37

121/11 = 11

121 = 11*11

If we say 11+11+11+...+11, and have 11 copies of these values added, then we get to a sum of 121

This is probably the easiest way to get the answer assuming repeated values are allowed.

You can stop here if your teacher allows you to use repeated values. If not, then move onto the next section.

-----------

If your teacher requires you to add 11 <u>different</u> numbers, then you can follow this procedure

  1. Write out eleven copies of "11" in a sequence
  2. Subtract 2 from the first "11" (to get 9) and add it to the last copy of "11" (to get 13)
  3. Subtract 4 from the second "11" (to get 7) and add it to the second to last copy of "11" (to get 15)
  4. Subtract 6 from the third "11" (to get 5) and add it to the third to last copy of "11" (to get 17)
  5. Subtract 8 from the fourth "11" (to get 3) and add it to the fourth to last copy of "11" (to get 19)
  6. Finally, subtract 10 from the fifth "11" (to get 1) and add it to the fifth to last copy of "11" (to get 21)

After carefully following those steps, you'll get this sequence (in the exact order shown):

{9, 7, 5, 3, 1, 11, 21, 19, 17, 15, 13}

There are three properties to notice of this sequence

  1. It's composed of two decreasing arithmetic sequences {9, 7, 5, 3, 1} and {21, 19, 17, 15, 13}
  2. The 11 in the middle hasn't been changed from the original sequence of nothing but "11"s.
  3. You should find that the terms of this new sequence add to 121.

That sequence we got sorts to {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21}

and we can say 1+3+5+7+9+11+13+15+17+19+21 = 121

<h3>Answer: 1+3+5+7+9+11+13+15+17+19+21 = 121</h3>

5 0
2 years ago
fathi has $1.10 in his printing account. each sheet of paper he uses reduces his printing account balance by $0.25. Fathi wants
Oksana_A [137]

Answer:

IF THE question is After Fathi prints, what will be the balance in his printing account?

then it is: $1.9

There are 47 pages.

Printing on both sides would divide the number of pages into half.

47/2 = 23.5

2 pages on each side would mean 4 pages on one sheet. Therefore, the number of pages will be further divided by 2.

23.5/2 = 11.75

There cannot be 11.75 pages so we will round it up to 12 pages.

Each page costs $0.25 so 12 pages will cost:

12 x 0.25 = $3

Faithi has $1.1 so new account balance will be:

1.1 - 3 = $-1.9

Therefore, Fathi's balance in his printing account would be negative $1.9.

6 0
3 years ago
Read 2 more answers
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