Y=5-2x
x^2 + (5-2x)^2 = 25
x^2 + 25-20x+4x^2 = 25
x^2 +4x^2-20x+25=25
5x^2 -20x=0
x=0 and y=5
Answer:
8,11,14,17,20,23,26
Step-by-step explanation:
Q = 3n+ 5
an=3n+5
a1=3(1)+5=8
a2=3(2)+5=11
a(3)=3(3)+5=14
a4=3(4)+5=17
a5=3(5)+5=20
a6=23
a7=26
Please check the attached picture
Answer:
See below in bold.
Step-by-step explanation:
1. The 3 angles in a triangle add up to 180 degrees.
So x = 180 - (55 + 25)
= 180 - 80
= 100 degrees.
2. The 4 angles in a quadrilateral add up to 360 degrees,, so
3x + 127 + 54 + 119 = 360
3x + 300 = 360
3x = 360 - 300
3x = 60
x = 20 degrees.
3. Exterior angle
= 94 + 42
= 136 degrees.
Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
(1)
By Quadratic Formula:
, 
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
