In order to use the remainder theorem, you need to have some idea what to divide by. The rational root theorem tells you rational roots will be from the list derived from the factors of the constant term, {±1, ±5}. When we compare coefficients of odd power terms to those of even power terms, we find their sums are equal, which means -1 is a root and (x +1) is a factor.
Dividing that from the cubic, we get a quotient of x² +6x +5 (and a remainder of zero). We recognize that 6 is the sum of the factors 1 and 5 of the constant term 5, so the factorization is
... = (x +1)(x +1)(x +5)
... = (x +1)²(x +5)
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The product of factors (x +a)(x +b) will be x² + (a+b)x + ab. That is, the factorization can be found by looking for factors of the constant term (ab) that add to give the coefficient of the linear term (a+b). The numbers found can be put directly into the binomial factors to make (x+a)(x+b).
When we have 1·5 = 5 and 1+5 = 6, we know the factorization of x²+6x+5 is (x+1)(x+5).
Answer:
1 minute
Step-by-step explanation:
We can see that Lisa types 165 words in 3 mins.
So she types 55 words in 1 minute.
How did I work that out?
Well, all you really do is 
which is equal to 
if you divide top and bottom by 3. Anything divided by 1 is itself.
Answer:
3/4
Step-by-step explanation:
Answer:
a
Step-by-step explanation:
to be a function, every x has to have exactly one y, so there can't be the same number x twice wirh different y's
