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nydimaria [60]
3 years ago
9

Can I get help with this please

Mathematics
1 answer:
drek231 [11]3 years ago
3 0

Answer:

3)  1 5/6 mi

4)  a. 4 cm, 6 ft

    b. 6.4 cm, 9.6 ft

    c. same as part a

Step-by-step explanation:

3) Each of the given distances appears twice in the sum of side measures that is the perimeter. Hence by walking the perimeter twice, Kyle walks each of the given distances 4 times. His total walk is ...

  4×1/3 + 4×1/8 = 4/3 + 4/8

  = 1 1/3 + 1/2 = 1 2/6 + 3/6

  = 1 5/6 . . . . . miles

___

4) Since the figure is rectilinear (all angles are right angles, and all sides are straight lines), the sum of partial dimensions in one direction is equal to the whole dimension in that direction.

a. 8 cm = 4 cm + x

  8 cm - 4 cm = x = 4 cm

The distance in the room is ...

  (4 cm)×(1.5 ft/cm) = 6 ft

b. 10.3 cm = 3.9 cm + y

  10.3 cm - 3.9 cm = y = 6.4 cm

The distance in the room is ...

  (6.4 cm)×(1.5 ft/cm) = 9.6 ft

c. The answer to part b was obtained in the same way as the answer to part a.  The unknown dimension is the difference of given dimensions. The actual length in the room is the model length multiplied by the inverse of the scale factor.

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x =10

Step-by-step explanation:

Given

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3 0
3 years ago
Which graph best represents the relationship between time and the number of teams registered?
alexdok [17]
<h2>Explanation:</h2><h2></h2>

The complete question is in the attached file. So we have to choose between two graphs. On of them is a linear model while the other is an exponential model. From the statements, we have a relationship between time and the number of teams registered. So we can establishes variables in the following form:

x:\text{Time} \\ \\ y:\text{Number of teams registered}

We also know that each week 6 teams register to participate, so:

\bullet \ \text{For week 0:} \rightarrow \text{0 teams registered} \\ \\ \bullet \ \text{For week 1:} \rightarrow \text{6 teams registered} \\ \\ \bullet \ \text{For week 2:} \rightarrow \text{12 teams registered (Because 6+12)} \\ \\ \bullet \ \text{For week 3:} \rightarrow \text{18 teams registered (Because 12+6)}

As you can see, as x increases one week, y increases at a constant ratio of 6. Therefore, this can be modeled by a linear function given by the form:

y=6x

In conclusion, <em>the linear model (first graph below) is the one that bests represents  the relationship between time and the number of teams registered.</em>

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