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dimaraw [331]
4 years ago
9

AB has endpoints at (-1, -1) and (-2, -4). Its transformation A'B' has endpoints at (-2, -2) and (-4, -8). What type of transfor

mation occurred? Are lengths of segments affected by this type of transformation? Justify.
Mathematics
1 answer:
Nataliya [291]4 years ago
5 0
A dilation has occurred.
Yes the length has been affected; specifically it has been doubled (twice as long).

----------------------------------------------

Notice how the coordinates of (-1,-1) are doubled to get (-2,-2). Likewise when we go from (-2,-4) to (-4,-8). This shows us that we are dilating with a scale factor of 2, with the origin being the center of dilation. The scale factor 2 tells us that
new length = 2*(old length)

So the old figure is not going to be congruent to the new figure

To fully prove that the length has been doubled, you can use the distance formula to calculate the distance from (-1,-1) to (-2,-4) and that distance is sqrt(10) = 3.16 roughly

While the distance from (-2,-2) to (-4,-8) is 2*sqrt(10) = 6.32 roughly, so the distance has been doubled
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two buses leave towns 604 mi apart at the same time and travel toward eachother. One bus travels 9 mi/h faster than the other on
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Answer:

s = 71 mph, and s+9 = f = 80 mph

Step-by-step explanation:

The distances the two busses travel add up to 604 mi.

Letting f be the faster speed and s the slower.  Then f = s + 9 (mph).

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The common difference of an ap is -2 find its sum of first term is hundred and last term is minus 10
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Answer:

The sum of the arithmetic progression is 2520

Step-by-step explanation:

The sum, Sₙ, of an arithmetic progression, AP, is given as follows;

S_{n}=\dfrac{n}{2}\cdot \left (2\cdot a+\left (n-1  \right )\cdot d  \right )

Where;

n = The nth term of the progression

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d = The common difference = -2

Given that the last term = -10, we have;

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Therefore, the sum of the 56 terms of the arithmetic progression is S_{56}=\dfrac{56}{2}\cdot \left (2\cdot 100+\left (56-1  \right )\cdot (-2)  \right )

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