There's no picture but soon as you add one so I can see what I'm answering then I will immediately help!
2.09, 2.190, 2.37, 2.432
Hope this helps!
Given:
The scale of a map is 
.
The distance between two buildings is 60 miles.
To find:
The distance between the given building on the map.
Solution:
We have,
It means, 80 miles in real life = 
on the map.
1 mile in real life = 
on the map.
60 mile in real life = 
on the map.
= 
on the map.
= 
on the map.
Therefore, the buildings are apart on the map.
Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
