Question

Calculate the area of the triangle ABC with altitude, CD, given:A(-6,-4), B(6,5), C(-1,6), and D(2,2). Round your answer to the nearest tenth if necessary.

Answer 1

Answer:

The answer to your question is 37.5 u²

Step-by-step explanation:

Formula

Area of a triangle = $\frac{base x height }{2}$

Base

dAB = $\sqrt{(x2 - x1)^{2}- (y2 - y1)^{2} }$

dAB = $\sqrt{(-6 -6)^{2} + (-4 -5)^{2} }$

dAB = $\sqrt{144 + 81}$

dAB = $\sqrt{225}$

dAB = 15 u

height

dCD =  $\sqrt{(x2 - x1)^{2}- (y2 - y1)^{2} }$

dCD = $\sqrt{(2 +1)^{2} + (2 - 6)^{2} }$

dCD = $\sqrt{9 + 16}$

dCD = $\sqrt{25}$

dCD = 5 u

Area

        = $\frac{15 x 5}{2}$

        = 37.5 u²