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3 years ago

........................................ ....,.........

Mathematics

2 answers:

Over [174]3 years ago

8 0

Thank you so much for the points

Have a great day/night

Pavel [41]3 years ago

5 0

...??????????? Okkkkkkk

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A farmer is tracking the number of soybeans his land is yielding each year. He finds that the function f(x) = −x2 + 20x + 100 mo

labwork [276]

Answer:

The farmer should expect to LOSE 10 pounds of soybeans per acre per year

Step-by-step explanation:

f(x)=-x^2 + 20x + 100

just find how many soybeans his land will yield (per acre) after 10 and 20 years:

After 10: 200 pounds of soybeans/acre

After 20: 100 pounds of soybeans/acre

Because 10 years have passed and they lost 100 pounds of soybean production per acre, the farmer should expect to lose 10 pounds of soybeans per acre per year (-10 pounds of soybeans per acre/year)

3 0

3 years ago

IM GIVING BRAINLIEST!! suppose F is a 10-newton vector direction 60 degrees north of east and g is a 12-newton vector directed 4

Sonbull [250]

Answer: The magnificent of east and g is a round out of the fraction that is in direct to 32 degrees and the other direction of the resultant 10 = 12 + F

45 = 60 + F.

8 0

3 years ago

Which ordered pair gives a solution of the system of equations represented in the graph below? O A (2.5, 1.5) OB. (2.5, 1.5) Oc.

olasank [31]

Answer:

b highlights my beautiful

6 0

3 years ago

Read 2 more answers

Della lives in a city where she pays federal and local taxes on her income. On her last paycheck, 31% of her income was taken ou

Anit [1.1K]

Answer:

Step-by-step explanation:

If you add the presents then calculate that percent off of of her last paycheck you will find your answer

8 0

3 years ago

Can anyone help me solve this? Please and thank you!

AveGali [126]

It's the sum of a geometric sequence.

Let's rewrite it a bit:

$\displaystyle\\\sum_{n=1}^{10}8\left(\dfrac{1}{4}\right)^{n-1}=8\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n\cdot \left(\dfrac{1}{4}\right)^{-1}=8\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n\cdot 4=32\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n$

And now let's calculate this sum $\displaystyle \sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n$ :

$S_n=\dfrac{a(1-r^n)}{1-r}\\\\a=\dfrac{1}{4}\\n=10\\r=\dfrac{1}{4}\\\\S_{10}=\dfrac{\dfrac{1}{4}\cdot\left(1-\left(\dfrac{1}{4}\right)^{10}\right)}{1-\dfrac{1}{4}}=\dfrac{\dfrac{1}{4}\cdot\left(1-\dfrac{1}{1048576}\right)}{\dfrac{3}{4}}=\dfrac{\dfrac{1048575}{1048576}}{3}=\dfrac{1048575}{3145728}=\\=\dfrac{349525}{1048576}$

Now let's calculate the initial sum:

$\displaystyle 32\cdot \sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n=32\cdot \dfrac{349525}{1048576}=\dfrac{349525}{32768}\approx10.67$

8 0

2 years ago