3 years ago

Given △ABC, sin(A) = A. cos(B) B. sin(B) C. cos(C) D. tan (C)

Mathematics

2 answers:

irinina [24]3 years ago

7 0

the answer is cos(C).

kozerog [31]3 years ago

6 0

we know that

In a right triangle ABC

m∠A+m∠C= $90\°$ -------> by complementary angles

$sin(A)=cos (C)\\and\\cos(A)=sin (C)$

therefore

<u>the answer is the option</u>

C. cos(C)

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