Question

Given △ABC, sin(A) = A. cos(B) B. sin(B) C. cos(C) D. tan (C)

Answer 1

the answer is cos(C).

Answer 2

we know that

In a right triangle ABC

m∠A+m∠C=$90\°$ -------> by complementary angles

so

$sin(A)=cos (C)\\and\\cos(A)=sin (C)$

therefore

the answer is the option

C. cos(C)