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Rus_ich [418]
3 years ago
15

Victoria builds a dollhouse in the shape of a right prism, as show below

Mathematics
1 answer:
Snezhnost [94]3 years ago
7 0
Your answer is correct
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I will give brainliest for the best awnser
hodyreva [135]

I worked it out and I got south Africa

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3 years ago
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The length of the midsegment of a triangle is always half the length of the side it is parallel to true or false
Vladimir [108]
True. The midsegment of a triangle is halfway up the triangle, and since the top half and the full triangle are similar triangles, its dimensions are proportional.

This means half the height will give half the base (midsegment). So the midsegment is always half the length of the side it's parallel to.
3 0
2 years ago
The following equation describes a circle.
Simora [160]

Answer:

Center = (5, -2)  and radius = √33

Step-by-step explanation:

The equation of a circle is given by the formula;

(x-a)² + (y-b)² = r² ; where (a,b) is the center of the circle and r is the radius of the circle.

In this case;

2x² - 20x + 2y² + 8y =40 ;

Dividing both sides of the equation by 2 we get;

x² - 10x + y² + 4y = 20

we can then use the completing the square on both x and y terms.

x² - 10x + y² + 4y = 20

x² + 2(-5)x + 25 + y² + 2(2) y + 4 = 20 +9 + 4

In standard form we get;

(x-5)² + (y+2)² = 33

Therefore;

Center = (5, -2)  and radius = √33

3 0
2 years ago
Help please I'm not getting this at all. I'll send the whole picture ​
Vikentia [17]

Answer:

true. hope this helps!!

8 0
2 years ago
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The average (arithmetic mean) of y numbers is x. If 30 is added to the set of numbers, then the average will be x − 5. What is t
Alenkasestr [34]

Answer:

y = \frac{1}{5}(x^{2}-35x)

Step-by-step explanation:

Let the total numbers are n.

If the average of y numbers is x then we can form an equation

\frac{y}{n}=x

⇒ \frac{n}{y}=\frac{1}{x}

⇒ n = \frac{y}{x} --------(1)

Now 30 is added to the set of numbers then average becomes (x - 5)

\frac{y+30}{n+1}=(x-5)

⇒ \frac{(n+1)}{(y+30)}=\frac{1}{(x-5)}

⇒ (n + 1) = \frac{y+30}{x-5}

⇒ n = \frac{y+30}{x-5} - 1 ----- (2)

Now we equate the values of n from equation 1 and 2

\frac{y}{x} = \frac{y+30}{x-5} - 1

y(x - 5) = x(y + 30) - x(x - 5)  [ By cross multiplication ]

xy - 5y = xy + 30x - x² + 5x

xy - xy - 5y = 35x - x²

-5y = 35x - x²

x² - 35x = 5y

y = \frac{1}{5}(x^{2}-35x)

6 0
3 years ago
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